2X^3+(2a+23)X^2+(10-7a)X+3a-11分解因式
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2X^3+(2a+23)X^2+(10-7a)X+3a-11分解因式
有类似提问,
2x^3+(2a+23)x^2+(10-7a)x+3a-11
=2x^3-x^2+x^2+(2a+23)x^2+(10-7a)x+3a-11
=x^2*(2x-1)+(2a+24)x^2-(a+12)x+(a+12)x+(10-7a)x+3a-11
=x^2*(2x-1)+(a+12)x(2x-1)+(22-6a)x-(11-3a)
=x^2*(2x-1)+(a+12)x(2x-1)+(11-3a)(2x-1)
=(2x-1)(x^2+(a+12)+11-3a).但我不知道怎么想上去,
有类似提问,
2x^3+(2a+23)x^2+(10-7a)x+3a-11
=2x^3-x^2+x^2+(2a+23)x^2+(10-7a)x+3a-11
=x^2*(2x-1)+(2a+24)x^2-(a+12)x+(a+12)x+(10-7a)x+3a-11
=x^2*(2x-1)+(a+12)x(2x-1)+(22-6a)x-(11-3a)
=x^2*(2x-1)+(a+12)x(2x-1)+(11-3a)(2x-1)
=(2x-1)(x^2+(a+12)+11-3a).但我不知道怎么想上去,
![2X^3+(2a+23)X^2+(10-7a)X+3a-11分解因式](/uploads/image/z/15583581-45-1.jpg?t=2X%5E3%2B%282a%2B23%29X%5E2%2B%2810-7a%29X%2B3a-11%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F)
如果你不是很理解的话可以用比较传统的方法
先把含有a项与没a项分开得:
原式=(2x^3+(23x^2)+10x-11)+a(2x^2-7x+3)
再进行因式分解会容易很多
接上面:=(2x^3+2x^2+21x^2+10x-11)+
(2ax^-7ax+3a)
=(2x^2(x+1)+(21x-11)(x+1))+a(2x-1)(x-3)=(x+1)(2x^2+21x-11)+a(2x-1)(x-3)
=(x+1)(x+11)(2x-1)+a(2x-1)(x-3)
=(2x-1)((x+1)(x+11)+a(x-3))
=(2x-1)(x^2+(a+12)x+11-3a).
先把含有a项与没a项分开得:
原式=(2x^3+(23x^2)+10x-11)+a(2x^2-7x+3)
再进行因式分解会容易很多
接上面:=(2x^3+2x^2+21x^2+10x-11)+
(2ax^-7ax+3a)
=(2x^2(x+1)+(21x-11)(x+1))+a(2x-1)(x-3)=(x+1)(2x^2+21x-11)+a(2x-1)(x-3)
=(x+1)(x+11)(2x-1)+a(2x-1)(x-3)
=(2x-1)((x+1)(x+11)+a(x-3))
=(2x-1)(x^2+(a+12)x+11-3a).
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