如图,∠1=∠2,AD=AE,AB=AC,请说明BD=CE
如图,AB=AC,∠BAC=90°,BD⊥AE于D,CE⊥AE于E 说明1、AD=CE 2、BD=AE
如图,已知AB=AC,AD=AE,BD=CE.试说明:∠BAC=∠DAE
如图,已知AB=AC,AD=AE,试说明:BD=CE.
如图,AB=AC,AD=AE,BD=CE,BD与CE相较与点o,说明∠cab=∠ead=∠boc
如图,已知AB=AC,AD=AE,BD=CE,求证:∠3=∠1+∠2
如图,AB=AC,AD=AE,∠1=∠2,试证明BD=CE
如图,AB=AC,AD=AE,BD=CE.(1)若AD⊥AE,求证:BD⊥CE;(2)若BD⊥CE,求证:∠BAE+∠C
如图,AE⊥AB,AD⊥AC,AB=AE,∠B=∠E,猜想BD与CE的位置关系,说明理由.
已知:如图5,AE⊥AB,AD⊥AC,BD=CE,BD⊥CE于O,试说明:AE=AB.
如图,已知AB=AC,AD=AE,∠EAD=∠CAB,BD与CD相较于点O,求证说明:BD=CE.
如图所示,已知AB=AC,AD=AE,请说明BD=CE
如图,在△ABC中,AB=AC,AD⊥BD,AE⊥CE,且AD=AE,BD和CE交于点O.说明∠EAB=∠DAC