搜狗做题网不是很难吧
来源：学生作业帮 编辑：搜狗做题网作业帮 分类：数学作业 时间：2024/08/19 16:13:39
(2+1)(4+1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1) = 老师我只要咋算的，不要答案 谢谢了啊 (*^__^*) 嘻嘻
解题思路： 添加因式（2-1），套用平方差公式，运算简便。
解题过程：
解：
(2+1)(4+1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1)
=（2-1）(2+1)(4+1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1)
=（4-1）(4+1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1)
=（8-1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1)
根据规律，计算
=(2097152-1))(2097152+1)
=20971522-1
最终答案：略
解题过程：
解：
(2+1)(4+1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1)
=（2-1）(2+1)(4+1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1)
=（4-1）(4+1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1)
=（8-1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1)
根据规律，计算
=(2097152-1))(2097152+1)
=20971522-1
最终答案：略