不是很难吧
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(2+1)(4+1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1) = 老师我只要咋算的,不要答案 谢谢了啊 (*^__^*) 嘻嘻
![不是很难吧](/uploads/image/z/15257005-61-5.jpg?t=%E4%B8%8D%E6%98%AF%E5%BE%88%E9%9A%BE%E5%90%A7)
解题思路: 添加因式(2-1),套用平方差公式,运算简便。
解题过程:
解:
(2+1)(4+1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1)
=(2-1)(2+1)(4+1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1)
=(4-1)(4+1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1)
=(8-1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1)
根据规律,计算
=(2097152-1))(2097152+1)
=20971522-1
最终答案:略
解题过程:
解:
(2+1)(4+1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1)
=(2-1)(2+1)(4+1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1)
=(4-1)(4+1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1)
=(8-1)(8+1)(16+1)(32+1)(64+1)(128+1)......................(1048576+1)(2097152+1)
根据规律,计算
=(2097152-1))(2097152+1)
=20971522-1
最终答案:略