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来源:学生作业帮 编辑:搜狗做题网作业帮 分类:数学作业 时间:2024/08/08 19:56:44
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![](http://img.wesiedu.com/upload/4/79/4794efd2d57fa03ffd7135b56ab00dbe.jpg)
![](http://img.wesiedu.com/upload/4/79/4794efd2d57fa03ffd7135b56ab00dbe.jpg)
![见图片](/uploads/image/z/15147237-21-7.jpg?t=%E8%A7%81%E5%9B%BE%E7%89%87)
极限选D,
lim[(x-1)/(√x-1)]
=lim(x-1)/lim(√x-1)
x->0,lim(x-1)->-1,
x->0,lim(√x-1)->-1,
所以原式lim[(x-1)/(√x-1)]=1
3.答案是1
n->正无穷时,
lim(an)=lim[n/(n-2009.9)]-lim[2009.9/(n-2009.9)]
=1-0=1
4.A(n+1)=1/2*An +1 => A(n+1) -2=1/2* (An-2)
所以An - 2是等比数列,公比为1/2
lim(An-2)=0
所以lim(An)=0
lim[(x-1)/(√x-1)]
=lim(x-1)/lim(√x-1)
x->0,lim(x-1)->-1,
x->0,lim(√x-1)->-1,
所以原式lim[(x-1)/(√x-1)]=1
3.答案是1
n->正无穷时,
lim(an)=lim[n/(n-2009.9)]-lim[2009.9/(n-2009.9)]
=1-0=1
4.A(n+1)=1/2*An +1 => A(n+1) -2=1/2* (An-2)
所以An - 2是等比数列,公比为1/2
lim(An-2)=0
所以lim(An)=0