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Aluminum reacts with chlorine gas to form aluminum chloride

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Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction:
2Al(s)+3Cl2(g)→2AlCl3(s)
What is the maximum mass of aluminum chloride that can be formed when reacting 23.0g of aluminum with 28.0g of chlorine?
Express your answer to three significant figures and include the appropriate units.
我算的是23.4g 但是不对
Aluminum reacts with chlorine gas to form aluminum chloride
若Al完全反应,需要23/27*3*35.5=90.7g的Cl2,说明Al过量,而Cl完全反应
所以,Cl2完全反应,生成28/(3*71)*2*(27+3*35.5)=35.1g
再问： 2Al(s)+3Cl2(g)→2AlCl3(s) 3 2 28/(35.5*2) x 然后求出xmol的AlCl3 然后再求它的质量吗？
再答： 对的，就是这个意思。
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