x除以3 y除以6=17,怎样分解x y=多少-搜答案-搜狗做题网

17除以3除以1/6=

17除以3除以1/6=3分之17x6=34

把3x＋2y转化成分式.同时÷xy再算就行了

/>2x+y=(4x-y-1)/2=(10+6x+2y)/4=(5+3x+y)/24x+2y=4x-y-1……1式3y=-1y=-1/34x+2y=5+3x+y……2式x=5-y=5+1/3=16/3

y=(2x+3)/(x-1)=[2(x-1)+2+3]/(x-1)=2+5/(x-1)x＜1,∴5/(x-1)＜0,∴y＜2或∵x＜1,x-1≠0,变换得y(x-1)=2x+3,即x=(3+y)/(y

x/10=y/8=z/9=(x+y+z)/(8+9+10)=(y+z)/(8+9)所以：(x+y+z)/(8+9+10)=(y+z)/(8+9)所以：(x+y+z)/(y+z)=(8+9+10)/(8

x/3+y/4=9/10(1)x/5+y/4=7/10(2)(1)-(2)得：2x/15=1/5x=3/2代入(1)得：y/4=2/5y=8/5所以：方程组的解是：x=3/2；y=8/5

1除以2x+3y=-61除以2x+y=2则：2x+3y=-1/6(1)2x+y=1/2(2)(1)-(2)得：2y=-2/3y=-1/3代入(2)得：2x=5/6x=5/12所以,方程组的解是：x=5

有什么问题的亲欢迎向我或者我的团队【定向求助】哦我们将在第一时间内尽力为您解答

你题目发错了吧

我说老大,你说明白点儿,是X+Y/2-Y/3=64(X+Y)-5(X-Y)=2还是(X+Y)/(2+X)-Y/3=64(X+Y)-5(X-Y)=2又或者(X+Y)/2+(X-Y)/3=64(X+Y)-

1÷(2÷3)÷(3÷4)÷(4÷5)÷(5÷6)÷(6÷7)=1÷2×3÷3×4÷4×5÷5×6÷6×7=1÷2×7=0.5×7=3.5明白请采纳,有新问题请求助,

-0.2X/2=Y/3=Z/-7X/2=Y/33X=2YX=2/3YY/3=Z/-7-7Y=3ZZ=-7/3YX+Y+Z=(2/3Y+Y-7/3Y)/(Y+7/3Y)=(-2/3Y)/(10/3Y)=

令x/3=y/4=z/6=k(xy+yz+xz)/(x^2+y^2+z^2)=(12+18+24)/(9+16+36)=54/61再问：真的吗确定再答：这道题我都回答过，有人问过的。确定

因为X/3=Y/4=M/5,则令X/3=Y/4=M/5=h可得：X=3h,Y=4h,mM=5h,又因为x+y+m=6则带入得：3h+4h+5h=12h=6h=1/2所以X=3h=3/2,Y=2,M=5

令x除以2=y除以3=z除以4=k则x=2k,y=3k,z=4kx+y+z除以x-2y+3z=(2k+3k+4k)除以(2k-6k+12k)=9k除以8k=8分之9

方程两边都乘以6得：3x-2x=36解得x=36

+++++++++++++++++++++++++++++++++++++++++++++++++绝对值肯定是大于等于0的.所以|2x+6|=0,即x=-3；同理|3-y|=0,即y=3；所以y/x=

x=10

绝对值项恒非负,两绝对值项之和=0,两绝对值项分别=03x-y=0(1)x+y=0(2)(1)+(2)4x=0x=0,代入(2)y=-x=0(x-y)/(xy)无意义,因此题目错了.

共有5种算法：1/(2/3)/4/(5/6/7/8)/9=2.81/(2/(3/4))/(5/6/7/8)/9=2.81/(2/(3/4/5)/6/7/(8/9))=2.81/(2/(3/4/(5/6