通分(x-1)(1-x)
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1/(x+2),4x/(x²-4),2/(2-x)公分母是x²-4=(x+2)(x-2)1/(x+2)=(x-2)/(x²-4)4x/(x²-4)2/(2-x)
题目不明白.x平方+x分之1还是(x平方+x)分之1?“x平方+x分之1,x平方+2x+1分之-1”中“,”是什么东东
解(x+2)/x^2-2x=(x+2)/x(x-2)(x-1)/(x^2-4x+4)=(x-1)/(x-2)(x-2)再问:怎么有点没看懂?。。再答:是两个分式通分吗?那么如下解(x+2)/x^2-2
通分1/x平方-y平方和1/x平方+xy1/x平方-y平方=x/x(x+y)(x-y)1/x平方+xy=(x-y)/x(x+y)(x-y)通分x/x平方-4和x-1/(x-2)平方x/x平方-4=x(
1/(x²+2x)+1/(x²-x)=1/x(x+2)+1/x(x-1)=(x-1)/x(x+2)(x-1)+(x+2)/x(x+2)(x-1)通分后分母是x(x+2)(x-1)
1x³+1x²+-----=-----xx-1x²(2x+1)-12x³+x²-1x²+-----------=--------------
计算是结果相加还是怎么的?
1,(X×3X)/3X+1/3X=(3X^2+1)/3X2,X/2X+(6×2X)/2X=(X+12X)/2X=13/23,(X-1)/X^2-[(9×X^2)/X^2]=[X-1-(9X^2)]/X
上式分母分别为3x2(x+3)(x+3)(x-3)∴公分母为6x(x+3)(x-3)很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,
再问:4x-2x²是个整体再问:再答:
公分母是2(x+3)²(x-3)所以6-2x分之x-1=2(x+3)²(x-3)分之[-2(x-1)(x+3)²]x²-9分之6=2(x+3)²(x-
1/x²-y²=1/(X+Y)(X-Y)1/x²+xy=1/X(X+Y)通分1/x²-y²=X/X(X+Y)(X-Y)1/x²+xy=(X-
x-1\x^3-x,x+1\x^3-x1\2xx-y\x+y先因式分解再通分和约分再问:通分和约分的过程能详细列出来吗?谢谢。再答:1 1/x²+x=1/x(x+1)=x-1/x(x+1)
x/(x²+2x+1),(x-1)/(x²+x),1/(x²-1)式1:x/(x+1)²,式2:(x-1)/[x(x+1)],式3:1/[(x+1)(x-1)]
1/2x+3=2x-3/4x²-92/3-2x=-4x-6/4x²-92x+5/4x^2-9
1/ac;1/2b[通分]2b/2abc;ac/2abc1/x-1;4/x^2-1[通分]x+1/(x+1)(x-1);4/(x+1)(x-1)3/x-2;2/6-3x[通分]9/3(x-2);-2/
兄弟啊,你这题是不是1/(2X+2)+1/(x²+x)?如果是,那原式=1/2(x+1)+1/x(x+1)=(x+2)/2x(x+1)
原式的公分母为30x^2(x^2-1)然后分别乘以相同倍数即可很高兴为您解答,【学习宝典】团队为您答题.请点击下面的【选为满意回答】按钮,
1/x^2+x=1/x(x+1)=(x+1)/x(x+1)^2-1/x^2+2x+1=-1/(x+1)^2=-x/x(x+1)^2
解最简公分母为:2x(x+1)(x-1)x/(2x+2)=x²(x-1)/[2x(x+1)(x-1)]1/(x²+x)=2(x-1)/[2x(x+1)(x-1)]1/(x²