输入一批非零整数,当输入0时结束输入,分别求出这一批整数中的偶数.奇数的平均值.

//仅供参考#includeintmain(){intn,sum=0;while(scanf("%d",&n)==1&&n+1){if(n%2==0)printf("%d\n",n);elsesum+

如果觉得好,#includevoidmain(){inta[10],i;intpositive_num,negative_num,zero_num;positive_num=negative_num=

#include<stdio.h>inteven(intn){    if(n%2==0)     

/>1#include#includeintmain(){intx=0;while(1){printf("请输入x值:");scanf("%d",&x);if(x==0){break;}printf(

你的i, j赋上初值为0你求平均不用在循环体里算的, 只需统计i, j的值就行了, 跳出循环的时候算一次就OK了.另外,你求平均,av1,av2就要用float

#include/**希望你自己能够看得懂..利用了递归的思想*//**@author:banxi1988*@date:2010-12-12**/intcanuse(intx,intk){if(x

vari,k,n1,n2:integer;beginn1:=0;n2:=0;fori:=1to20dobeginreadln(k);ifk>0thenn1:=n1+1elseifk

#include<iostream>usingnamespacestd;intmain(){       cout&l

#includevoidmain(){inta=0;intb;intc=0;do{\x05scanf("%d",&b);\x05if(b!=0)\x05{\x05\x05if(b%2==0)\x05\

#include“stdio.h”voidmain(){intn;//输入的整数longsum=0;所有输入数的和,定义为long是为了防止溢出intflag=1;作为一个标记数while(flag)

PrivateSubForm_Click()DimsAsInteger,maxAsInteger,minAsInteger,nAsInteger,averageAsSingle,sumAsLongDo

Private Sub Command1_Click()    s1 = 0   &nbs

楼上的,100个数#includemain(){intj=0,k=0,l=0;int*p;inta[100];for(p=a;p

同学你是女的吧,我亲自来指导你~

importjava.util.Scanner;publicclassMain{publicstaticvoidmain(Stringargs[]){Scannerinput=newScanner(S

.你把做为结束符的0也算进去了吧.在循环里判定一下,如果是0不做MIN==NUMif（NUM!=0）MIN=MIN

importjava.util.Scanner;publicclassMain{publicstaticvoidmain(Stringargs[]){Scannerinput=newScanner(S

#include#includeintmain(){inta,sum=0;do{scanf("%d",&a);if((a/100)%10==3)sum+=a;}while(a!=0);printf("

//C++输入一组非零整数(以输入零作为输入结束标志)到一维数组中,设计程序,求出这组数的平均值,并统计出正数和负数个数#defineMAXNUM1000//数组的最大个数,你可以改#includeu

voidmain(){intx,i=0,j=0;floats1=0,s2=0,av1,av2;scanf("%d",&x);while(x!=0){if(x%2==0){s1=s1+x;i++}els