调用子函数求100以内所有素数

#include<iostream.h>#include"math.h"bool IsPrimeNum(int n){int k=(in

#Code:Python2.5list=range(101)foriinxrange(2,101):if(list[i]==0):continueforkinlist[i+1:101]:if(k%i=

k=sqrt(i);改成k=sqrt(i*1.0)看不懂你这个程序,一会帮你重新写一个#include#defineMAX30voidmain(){intn=1,s=0,i,j,k;for(i=1;i

#include#includeintis_prime(intn);intmain(){inti,sum=0;for(i=2;i

235711131719232931374143475359616771737983899725个

素数就是质数

PrivateSubCommand1_Click()Dima()Fori=100To1Step-1Forj=i-1To1Step-1IfiModj=0Thenn=n+1NextIfn=1Thenm=m

publicclassSuShuo{staticintk;publicstaticvoidmain(String[]args){inti,j;for(i=1;i

intP(intx){inta,b;b=(int)sqrt(x);for(a=2;ab)return1;elsereturn0;}是判断质数的函数,接下来的你自己去弄调用吧

fori=200to500flag=1forj=2toi+1ifimodj=0thenflag=0:exitfornextjifflag=1thens=s+i:prints,i

publicstaticvoidmain(String[]args){for(doublei=1;ibooleanflag=false;for(intj=2;jif(i%j==0){flag=true

素数235711131719232931374143475359616771737983899397偶数2468...

#include#includeboolisPrime(intnum){if(num!=2&&num%2==0)//除2以外的偶数都不是素数{returnfalse;}for(inti=3;i

#include#includeusingnamespacestd;intjust(intnum){for(inti=2;i

素数：2357111317192329　　31374143475359616771　　7379838997奇数：13579111315171921232527293133353739414345474

可以运行啊.你把scanf("%lf,%lf",&x1,&y1);里么的逗号改成空格scanf("%lf%lf",&x1,&y1);

prime函数有错!int prime(int N){    int i;    if(N

Programex;Vari:Byte;Functionf(x:Byte):Boolean;Varm,i:Byte;Beginm:=Trunc(sqrt(x));f:=True;Fori:=2TomD

一个一个算,又不麻烦2357111317192329313741434753596167717379838997如果是程序#include#includeintisPrime(intx);intmai

500以内的所有的素数23571113171923293137414347535961677173798389971011031071091131271311371391491511571631671