设计控制台应用程序输出正整数n计算s=1 (1 2)
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![设计控制台应用程序输出正整数n计算s=1 (1 2)](/uploads/image/f/7263936-0-6.jpg?t=%E8%AE%BE%E8%AE%A1%E6%8E%A7%E5%88%B6%E5%8F%B0%E5%BA%94%E7%94%A8%E7%A8%8B%E5%BA%8F%E8%BE%93%E5%87%BA%E6%AD%A3%E6%95%B4%E6%95%B0n%E8%AE%A1%E7%AE%97s%3D1+%281+2%29)
privatesubform_click()dimnaslong,snaslongn=inputbox("请输入n")fori=0tonsn=sn+2*i+1nextmsgbox"1+3+5+...(
#includemain(){inti,j,n,k=0;scanf("%d",&n);for(i=2;i
#includevoidmain(){inti,N,sum;while(scanf("%d",&N)){sum=0;for(i=1;i
usingSystem;usingSystem.Collections.Generic;usingSystem.Linq;usingSystem.Text;namespaceConsoleApplic
static void Main(string[] args){ //声明变量  
#includeintmain(intargc,char*argv[]){inti,a,b,sum=0,c;scanf("%d%d",&a,&b);if(a>b){c=a;a=b;b=a;}for(i
#includeintmain(){inta;intsum=0;scanf("%d",&a);if(a
#includemain(){inti,j,k,n;scanf("%d",&n);if(n
usingSystem;usingSystem.Collections.Generic;usingSystem.Linq;usingSystem.Text;namespacetest{classPro
//Note:YourchoiceisC++IDE#includeusingnamespacestd;longintSfun(constintN){longintsum=1;if(N==0||N==1
楼上的看清楚了,人家要的是程序方法一:modicomma.prg然后在出现的程序框中输入input"n="tonx=0form=1tonx=x+mendfor"n=",x按CTRL+W保存,然后在命令
publicintfn(intn){intsum=0,m=1;for(inti=1;i
int[]num=newint[4];inti,j;inttemp;Console.WriteLine("请输入4个数");for(i=0;iConsole.WriteLine("第{0}个数",(i
staticvoidMain(string[]args){intintInput=0;while(true){Console.Write("请输入一个大于0的正整数:");stringstrInput
PrivateSubCommand1_Click()Sum=1Fori=1ToText1.TextSum=Sum*iNextiPrintSumEndSub再问:那在窗体上输出九九乘法表??你会吗??真
1)输入一个数计算数的个数通过取模算法取出每位数存入数组将数组中元素立方运算后相加2)输入一个数利用itoa函数转换为字符串取出每个字符,减去48后做立方运算相加
#include#includevoidmain(){intfunc_sum(intn){intsum=1;for(inti=0;inum;cout
A=1;B=-1;C=1a+b+c=1a=c2a+b=1a-2b+4c=75a-2b=72a+b=15a-2b=7So:A=1;B=-1;Becuase:a=c;So:c=1;SO:a=1,b=-1;
#includeusingnamespacestd;voidmain(){intnum[10];inti;intmax,smax;cout