编写程序,计算数列1 1 2 2 3 3 4 之和
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1.用dowhile循环写出计算100以内奇数和的程序clearsettalkoffs=0i=1dowhilei
#include#includeintmain(void){intn;doublei,j,k;doubleres=0;printf("pleaseinputn:");scanf("%d",&n);i=
PrivateSubCommand1_Click()Dima,xAsSinglea=Val(Text1.Text)Ifa再问:x=x+a*0.2+3000*0.2怎么都乘0.2呀?
#includemain(){doublex,y;scanf("%lf",&x);if(x
x=[3,4,5,6,7,8,9,10];y=[4,5,6,7,8,9,10,11];z=21.89-9.87*x+8.09*y-7.98*x.*y-1.87*x.^2-7.98*y.^2z=1.0e
doublef(doublex){doubles=.0;if(x
#includeusingnamespacestd;#include/*编写程序,计算并输出下面数列前20项的和,结果取3位小数.(C++)2/1,3/2,4/3,5/4,6/5,7/6,8/7,……
#includevoidmain(){inti;doublesum=0;for(i=1;i
doublenum1,num2,num3,sum;num1=num2=num3=sum=0;for(intii==0;ii再问:看的不是太明白哦,能写的再清楚一点吗?再答:doublenum1,num
sum=sum+1/(5*i+1);这一句,1/(5*i+1)的值是整数的,所以它一直是0这样好像可以sum=sum+(double)1/(5*i+1);
#include <stdio.h>int main(){ float x, tax = 0;
#include"stdio.h"voidmain(){doublea,n,s=0;for(n=1;n
#include"stdafx.h"voidmain(){ints=0;for(intn=1;n
问题太多.1,第四行doubleresult,product,case;中case不能作变量名,保留字.2,第十行result=fact(i);函数参数太少,你下面定义的函数应该有2个参数3,case
“i=1”---->"i==1","i=2"------>"i==2"
;MOVAX,AANDAX,B;AX=aANDbMOVBX,AXORBX,B;BX=aXORbADDAX,BXADDAX,BX;AX=2*(aXORb)+aANDbADDAX,A;AX=a+2*(aX
#includevoidmain(){intn=1,N,i;scanf("%d",&N);if(N20)printf("shuruwuxiao!\n");else{for(i=1;i
这是一个等比数列!以flash中的AS为例:varsum=0;varj=1;for(vari=1;i
PrivateSubForm_Click() DimnAsInteger,sAsInteger n=0 s=0
用什么语言呢?C还是PASCAL、VB?再问:vc++再答:#include<stdio.h>main(){ longa[30],i; a[0]=1;a[1]=1;&n