求两圆x² y²-10x-10y=0,x² y² 6x 2y-40=0-搜答案-搜狗做题网

1.x=1y=1.72.2983.248189

(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=4x-2y-z-5x[6y-(x+y)]+x-(3y-10z)=4x-2y-z-30xy+5x²+5xy+x-3

(7x-10y)-(-10y-5x)=?

(7x-10y)-(-10y-5x)=7x-10y+10y+5x=12x再问：7x-10y+10y+5x似乎等于2x+10y再答：-10y+10y=0

25(x-y)^2+10(y-x)+1=25(x-y)^2-10(x-y)+1={5(x-y)-1}^2=(5x-5y+1)^2

10x-35y-4x+10y再答：6x-25y

5（x-y)'3+10(y-x)'2;

1.=5（x-y)'3+10(x-y)'2=5(x-y)'2(x-y-2)2.=(4a'2)'2-2*(4a'2)*(9b'2)+(9b'2)'2=(4a'2-9b'2)'2=(4a-3b)'2(4a

(x+2y)²-10(x+2y)+25=(x+2y-5)²9（2x-y）²-6(2x-y)+1=(3(2x-y)-1)²=(6x-3y-1)²(x+a

先化简[(x²+y²)-(x-y)²+2y(x-y)]/4y[(x²+y²)-(x-y)²+2y(x-y)]/4y=[x²+y&s

|x|+x+y=10|y|+x-y=12两式相加得|x|+|y|+2x=22.(1)两式相减得|x|-|y|+2y=-2.(2)所以-|y|+2y＜0若y＞0,则显然-y+2y＜0,即y＜0,矛盾若y

(x+y)-(2x+y/2)-(3x+y/6)-(4x+y/12)-(5x+y/20)-……-(10x+y/90)=x-2x-3x-4x-..-10x+y*(1-1/2-1/6-1/12-..1/90

(100X+Y)-(10Y+X)=(10Y+X)-(10X+Y)100X+Y-10Y-X=10Y+X-10X-Y99X-9Y=9Y-9X-18Y=-108XY=6X把Y=6X代入X+Y=7得X+6X=

-8(2x-y)-{7x-[6x+2y-(10x-8y)]}=-16x+8y-[7x-(6x+2y-10x+8y)]=-16x+8y-(7x-6x-2y+10x-8y)=-16x+8y-7x+6x+2

已知2x-y=10,式子[(x^2+y^2)-(x-y)^2+2y(x-y)]/4y=[x^2+y^2-x^2+2xy-y^2+2xy-2y^2]/4y=[4xy-2y^2]/4y=2y(2x-y)/

{(x,y) |x|+|y|

区域是一个正方形

由x^2+y^2-10x-10y=0与x^2+y^2-5x-5y-20=0得两圆的公共弦方程为x+y-4=0,圆x^2+y^2-10x-10y=0的圆心坐标为(5,5),半径为5倍根号2,(5,5)到

（1）x^2+y^2-4x+10y+29=0x^2-4x+4+y^2+10y+25=0(x-2)^2+(y+5)^2=0x=2y=-5剩下的自己解下面两个题目是不是写错了,没看懂

x^2+y^2-10x-10y=0(x-5)^2+(Y-5)^2=50X^2+Y^2+6X+2Y-40=0(X+3)^2+(y+1)^2=50公共弦所在的直线是两个方程式之差即16x+12y-40=0

等于.-3y-10x

若x≤0,|x|=-x|x|+x+y=10y=10代入x+|y|-y=12得x=12>0矛盾,∴x>02x+y=10①若y≥0,x+|y|-y=x=12y=10-2x∴yx-2y=12②联立①②解得x

x>y?x:y

判断X的数值是否大于Y的数值如果是则为真等式去X的值反之取Y的值