求x²-2x-3分之X的不定积分
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![求x²-2x-3分之X的不定积分](/uploads/image/f/5733863-71-3.jpg?t=%E6%B1%82x%C2%B2-2x-3%E5%88%86%E4%B9%8BX%E7%9A%84%E4%B8%8D%E5%AE%9A%E7%A7%AF%E5%88%86)
x≠-2,-3,-4
请采纳再答:
2/(x-2)+6x/(x²-4)=3/(x+2)乘以(x²-4)得2(x+2)+6x=3(x-2)2x+4+6x=3x-68x-3x=-6-45x=-10x=-2经检验,当x=-
解题思路:先解方程求出x,再化简另一分式并把x值代入计算即可解题过程:解:经检验是原方程的解。
{[(x+2)/(x^2-2x)]-[(x-1)/(x-2)]}/[(x+3)/x]={[(x+2)/(x^2-2x)]-[(x^2-x)/(x^2-2x)]}*[x/(x+3)]=[(-x^2+2x
x^2-x分之x+1-3x-3分之x+k=3x分之1(x+1)/x(x-1)-(x+k)/3(x-1)=1/3x[3(x+1)-x(x+k)]/3x(x-1)=(x-1)/3x(x-1)3x+3-x&
x=1/x,x²=1,x=±1;[(x²+2x-3)/(x-1)]/[(x+3)/(x²-3x+1)]=(x+3)(x-1)(x²-3x+1)/[(x-1)(x
x/(x^2+x+1)=-1/2即-2x=x^2+x+1x^2+3x+1=0(x-1)/(2x^2+x^3-1)/(x^2-x+1)=(x-1)/(2x^2+x^3-1)(x^2-x+1)=(x-1)
到底什么是分子?是不是(x+4)/0.2-(x-3)/0.5=2?则5(x+4)-2(x-3)=25x+20-2x+6=25x-2x=2-20-63x=-24x=-24÷3x=-8
(x-1)/3=(x+6)/2-1;2(x-1)=3(x+6)-6;2x-2=3x+18-6;x=-14;很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,
两边乘(x+3)(x-3)3(x+3)-(x-3)=183x+9-x+3=182x=6x=3经检验,x=3则分母x-3=0是增根,舍去所以方程无解
x²-2分之x²=33x²-6=x²2x²=6x²=3(1-x分之1-1+x分之1)除以(x²-1分之x+x)=[(1-x)(1+
x-3=1/x两边都乘以x得x^2-3=1x^2-3-1=0x^2-3+2=3
(x-1)(x-3)(x-4)(x-5)-(x-1)(x-2)(x-3)(x-5)=(x-1)(x-2)(x-4)(x-5)-(x-1)(x-2)(x-3)(x-4)(x-1)(x-3)(x-5)(x
X^2-3X+1=0,x不能为0,所以两边除以x得,x+1/x=3,x^2+1/x^2=(x+1/x)^2-2=7所以,X^3+1/X^3=(x+1/x)(x^2+1/x^2-1)=3*(7-1)=1
1、x=2时极小值为1;x=1时极大值为2;做法对原题一级导数为6x^2-18x+12=0得x=1,2取极值;求二级导数得12x-18把x=2、3分别带入大于零极小值小于零极大值.2答案为3x-3ar
(1-x)/3=-(2x+3)/5等于两边同时乘以155(1-x)=-3(2x+3)5-5x=-6x-9-5x+6x=-9-5x=-14
x=0,y=6x=3,y=4x=6,y=2x=9,y=0再问:为什么是这么多呢,怎么求的再答:要自然数解,也就是让x=0,解出y,让x=1,解出y,一直这样做下去,还要保证y也是自然数,取出合理的,最
x=4084y=1/9所以√x=2√y=1/3原式=4*(1/2)-2/3-9*y√y=2-2/3-1/3=1
x>2→x-2>0,故依基本不等式得y=(x^2-3x+3)/(x-2)=[(x-2)+1/(x-2)]+1≥2√[(x-2)·1/(x-2)]+1=3.∴x-2=1/(x-2),即x=3时,所求最小