求x^3 (9 x^2)^(1 2)dx-搜答案-搜狗做题网

=x^18+x^15+x^12+x^9+x^6+x^3+1+x^3-1+5-4分解因式把下面的18换成21就是了=(x^18+1)+(x^15+1)+(x^12+1)+(x^9+1)+(x^6+1)+

X(1+2+3+4+5+6+7+8+9+10+11)=1980,X66=1980等于30

f(x)=1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+.1/(x+9)(x+10)=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1

用数值算法求近似解吧,精确解基本不可能.

-再答：

x=3/2x(x^3-x)+x^2(5-x)-9=x^4-x^2+5x^2-x^3-9=x^4-x^3+4x^2-9=x^3(x-1)+(2x-3)(2x+3)=x^3(x-1)=(3/2)^3*(1

=9x^4+4(x+1)-3x^2-7x+1=9x^4-3x^2-3x+5=9x^4-3x(x+1)+5=9x^4-3x×3x^3+5=5

设x1=4-√3,x2=4+√3,是方程X^2-8X+13=0的两根所以X1^2-8X1+15=2X^4-6X^3-2X^2+18X+23=(X+1)^2*(X^2-8X+13)+10=10所以原式=

(x-2)(x²-6x-9)=x(x²-8x+15)x(x²-6x-9)-2(x²-6x-9)=x(x²-8x+15)x(x²-6x-9)-

原式=[x(x-3)/(x-3)²][(x-5)(x-6)/x(x-5)]-1=[x/(x-3)][(x-6)/x]-1=(x-6)/(x-3)-1=(x-6-x+3)/(x-3)=-3/(

1.求x^21+x^15+x^12+x^9+x^6+x^3+1被x^2+x+1除所得的余式答：原式=[x^21+x^18-x^18-x^15+2*x^15+2*x^12-x^12-x^9+2*x^9+

x-o.8x=6X=3012x-8x=4.8X=1.23x-8=16X=8x-0.7x=3.6X=127.5x-2x这题没有=

f(x)=(x-2)^2/(x+1)f(x)'=[2(x-2)(x+1)-1*(x-2)^2]/(x+1)^2=(x-2)(x+4)/(x+1)^2f(x)=(x^2+9)(x-3/x)f(x)'=(

lim(x→2)(x^2-3x+2)/(x^2+4x-12)=lim(x→2)(x-2)(x-1)/(x-2)(x+6)=lim(x→2)(x-1)/(x+6)=(2-1)/(2+6)=1/8

1.f(x)求导得f'(x)=6x²-18x+12,当f'(x)≥0时f(x)单调递增,X的取值范围即为递增区间当f'(x)≤0时f(x)单调递减,X的取值范围即为递减区间2.y求导得y'=

2x-3=0∴x=3/2x(x²-x)+x²(5-x)-9=x²(x-1)+x²(5-x)-9=4x²-9当x=3/2时上式=4×（3/2）²

把x2+7x+10化成(x+2）（x+5）同理就可以约分了最后约分成最简,把想=9/2代入,就可以啦

每两项合并,即(1+x)+(1+x)*x^2+(1+x)*x^4+(1+x)*x^6+(1+x)*x^8=0提取公因式(1+x),得到(1+x)(1+x^2+x^4+x^6+x^8)=0等式左边的两个

原式=X²-9=-6再问：这两个&#是？再答：你发的什么乱码原式=X平方-9=-6

3x³-x=1所以原式=9x^4-3x²+12x³-4x-3x+2001=3x(3x³-x)+4(3x³-x)-3x+2001=3x+4-3x+200