c语言随机输入判断能否被3整除
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/18 02:44:12
![c语言随机输入判断能否被3整除](/uploads/image/f/532648-64-8.jpg?t=c%E8%AF%AD%E8%A8%80%E9%9A%8F%E6%9C%BA%E8%BE%93%E5%85%A5%E5%88%A4%E6%96%AD%E8%83%BD%E5%90%A6%E8%A2%AB3%E6%95%B4%E9%99%A4)
inta=123;if(0==(a/100+(a/10)%10+a%10)%7)printf("能被7整除");elseprintf("不能被7整除");
#includevoidmain(){intn;printf("input:\n");scanf("%d",&n);if(n%3==0&&n%5==0)printf("yes\n");elseprin
#includevoidmain(){intN,status=0;printf("输入这个数:");scanf("%d",&N);if(N%3==0)status++;if(N%5==0)status
#includeintmain(void){intn,a;scanf("%d",&n);a=0;if(n%3==0)++a;if(n%5==0)++a;if(n%7==0)++a;if(a==0)pr
#includeintmain(intargc,char*argv[]){intnum;printf("输入一整数:");scanf("%d",&num);if(num%3==0&&num%5==0&
#include <stdio.h>void mian(){ int n; &
我把SCANF里的中文去掉就正常了.
这需要流程图啊.那真不会写1.intsum=0;chari;for(i=1;i
#include"stdio.h"main(){intx;printf("请输入一个数字:");scanf("%d",&x);if(x%3==0)printf("该数字能被3整除.");if(x%5=
a+b>cabs(a-b)再问:能编个完整的给我吗?谢谢。新手,看不懂啊……不胜感激再答:#includeinta,b,c;scanf("%d,%d,%d",&a,&b,&c);if(a>0&&b>0
#includeintmain(){intnum;inta;//百位intb;//十位intc;//个位scanf("%d",&num);a=num/100;//默认强制转为整型b=(int)(num
#includeintmain(){inta;intb=0,c=0,d=0;scanf("%d",&a);if(a%5==0)c=1;if(a%7==0)d=1;elseif(c==1&&d==1)p
以下是关键代码intnum;//这个是要你判断的数if(num%3==0&&num%5==0)//判断能否被整除printf("能被3和5整除");
#includevoidmain(){\x09longa;\x09printf("inputanumber:\n");\x09scanf("%d",&a);\x09if(a%3==0&&a%5==0&
各位数相加和能被3整除,那么这个数就能被3整除,如258各位数相加等于15,15能被3整除,那么258也能被3整除.能够被5整除的只要各位数是0或5就行啦.15和10都能被5整除.另外,0除以任何数都
inta,b;scanf("%d%d",&a,&b);while(a{intt=a;a=b;b=t;}if(a%b==0)printf("a能被b整除");elsepr
#includevoidmain(){intn;printf("pleaseinputthedata:\n");scanf("%d",&n);if(n%3==0&&n%5==0)printf("the
#includeintmain(){inta;intb=0,c=0,d=0;scanf("%d",&a);if(a%3==0)b=1;if(a%5==0)c=1;if(a%7==0)d=1;if(b*
楼主你好!你问的问题代码如下及运行截图:如果有不正确之处,望指正!谢谢!希望我的回答对你有帮助!#include<stdio.h>int main(){ int&nbs
intnumber;scanf("%d",&number);if(number%3==0&&number%5==0){printf("YES");}else{printf("NO");}