c语言输入一个圆的半径,求其周长和面积并输出-搜答案-搜狗做题网

#include<stdio.h>int min(int a,int b){return (a<b?a:b);}int max(in

#include"stdio.h"intmain(){ inta,b,c,min; scanf("%d%d%d",&a,&a

#include#definepi3.141592653intmain(){doubler;printf("输入半径：\n");scanf("%lf",&r);printf("周长为：\n");pri

#include"stdio.h"#include"time.h"#include"stdlib.h"#include"math.h"#defineNUM_OF_INT30#defineMAX(x,y

在输入半径的时候,语句改成scanf("%d",&r);不过你最好将半径定义成float型变量,格式的问题

voidmain(){floatr,s,l;floatpi=3.1415;printf("输入一个圆的半径:\n");scanf("%f",&r);if(

#include#definePI3.1415926\x05\x05voidmain()\x05{\x05doubler,s;scanf("%f",&r);s=PI*r*r;\x05printf("A

程序你看看吧,有问题再问,/>#include<stdio.h>int main(){ int i,t,t1; int a[10];&nb

你的i, j赋上初值为0你求平均不用在循环体里算的, 只需统计i, j的值就行了, 跳出循环的时候算一次就OK了.另外,你求平均,av1,av2就要用float

给你代码：#include <iostream>#include <cstdio>#include <cstring>using&nb

voidmain(){floatsum=0,avg=0,min=100,max=0;intfail=0;for(i=0;i>a;sum+=a;if(min>a)min=a;if(max

#includeintmain(){intr=0;floata=0,l=0;scanf("%d",&r);a=r*r*3.14;l=r*2*3.14;printf("面积:%f,周长:%f",a,l)

没明白

#includeintmain(){inta[7]={1,2,3,4,5,6,7},k[10];intm,i,j=0,h=0;scanf("%d",&m);for(i=0;i

#includeintmain(){intx[5][5];inti,j,sum1,sum2;printf("请依次输入5*5数组的25个元素：\n");for(i=0;i

#include"stdio.h"#definePI3.141592653//定义πintmain(void){floatC,A,V,r;printf("请输入半径：");//提示输入scanf("%

#...intr,b,dsin

//这样就可以了#include<stdio.h>#define N 10int main(){ int&nbs

#includevoidmain(){inta[5][5]={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25},i,

#includeintmain(){inta,b;scanf("%d%d",&a,&b);/*输入两个整数a和b*/printf("%d\n",a+b);/*输出a和b之和~*/return0;}