c语言四位正整数反向输出
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/13 18:15:09
voidmain(){intn=-1;while(n
//z2.cpp:定义控制台应用程序的入口点.//#include"stdafx.h"#include#includeusingnamespacestd;voidReverse(int&m)//m为4
#include <stdio.h>int main(){\x09int n;\x09int nConut = 0;\x09sc
#include"stdio.h"#include"time.h"#include"stdlib.h"intisprime(intn)//判断n是否是素数,是返回1,不是返回0{ inti;
main(){longinta;intb,c,d,e,f;scanf("%ld",&a);while(a>=1&&a=1&&a/10000=1&&a/1000=1&&a/100=1&&a/10=1&&
#includeintmain(){intn;scanf("%d",&n);do{printf("%d",n%10);}while(n/=10);printf("\n");return0;}
浮点数也是有有效范围的,通常说来,一个float只精确到小数点后6位(这个与硬件及编译器都有关),double精度更高些,但也是有限位的小数部分,所以当你的c不断增大,就会出现0了.再问:那这个代码除
voiddiv(inta,intb,intn){inti;intyushu=a%b;printf("%d.",a/b);for(i=0;i<n;i++){yushu*=10;printf("%d
#includeintmain(){intm[10],i,j=0,k;longn;scanf("%ld",&n);k=n;while(k>0){k/=10;j++;}i=j;while(i--){m[
#includevoidmain(){inta,i=0,b[3];printf("inputathreebitnumber\n");scanf("%d",&a);if(a>=100&&a=0;j--)
方法很多嘛随便来一个:#include#includevoidmain(){charp[10];char*q;inti=0;scanf("%s",p);q=p;while(*(q++))i++;q--
#include#includevoidmian(){intnum,i,temp[5];printf("请输入一个低于5位的整数\n");scanf("%d",&num);for(i=0;i
#include#includeintmain(){intoldnum;intnewnum=0;inttemp;printf("pleaseinputnumber\n");scanf("%d",&ol
#includeintmain(void){longintx;inty,i=1;printf("请输入一个不超过100000的整数:");//99999||x
#include#includeintmain(){longintnum;intindiv,ten,hundred,thousand,ten_thousand,place;printf("intput
#include <stdio.h>//最大的精度#define MAX_LENGTH 120//计算商int GetFactor(int 
PrivateSubCommand1_Click()d=Val(Text1)Print100*(dMod100)+Int(d/100)EndSu
#include"stdio.h"voidmain(){intx,a,b,c,d,e,n,j;printf("请输入一个不多于5位的正整数\n");scanf("%d",&x);a=x/10000;b
#include#defineMAXN20intmain(){intn,t,k=0;intia[MAXN];printf("请输入一个整数:");scanf("%d",&n);while(t=n%10
#include#includeintmain(void){\x09intnum;\x09do\x09{\x09\x09printf("请输入一个不大于四位的数据:\n");\x09\x09scanf