C语言任意输入n个整数,分别统计奇数的和.奇数的个数.偶数的和.偶数的个数.
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![C语言任意输入n个整数,分别统计奇数的和.奇数的个数.偶数的和.偶数的个数.](/uploads/image/f/529904-56-4.jpg?t=C%E8%AF%AD%E8%A8%80%E4%BB%BB%E6%84%8F%E8%BE%93%E5%85%A5n%E4%B8%AA%E6%95%B4%E6%95%B0%2C%E5%88%86%E5%88%AB%E7%BB%9F%E8%AE%A1%E5%A5%87%E6%95%B0%E7%9A%84%E5%92%8C.%E5%A5%87%E6%95%B0%E7%9A%84%E4%B8%AA%E6%95%B0.%E5%81%B6%E6%95%B0%E7%9A%84%E5%92%8C.%E5%81%B6%E6%95%B0%E7%9A%84%E4%B8%AA%E6%95%B0.)
//#includevoidmain(){intm,n,i,min,max;printf("Pleaseinputm,n:\n");scanf("%d%d",&m,&n);min=mn?m:n;if(
楼上是C++写的,这个是C语言版的#include#includeintmain(){intcount;int*arrayLenth;int**intArray;int*elem1,*elem2;in
#includevoidsx(intx[],intn){inti,j,t;for(i=0;i
你的程序中判断素数并加和的部分有问题在你的基础上修改如下PS:main不需要改动# include <stdio.h>int SumPrime(int&nbs
#include"stdio.h"intmain(){inta[10][10]={0};intn,i,j,sum1=0,sum2=0;scanf("%d",&n);for(i=0;i
只学循环完全可以办到,关键是要动脑啊#includevoidmain(){\x09intn,m,max,i;\x09max=0;\x09printf("PleaseInputANumber:\n");
#include <stdio.h>;int main(int argc, char **argv) {
#include "stdio.h"int main(){ int count1=0,count2=0,i;&nbs
main(){inti,n,sum=0;scanf("%d",&n);n*=2;for(i=1;i
#includeintStrchr(chars[],charch){intl,i;intj=0;l=strlen(s);for(i=0;i
#includevoidmain(){inti,n,m,jh=0,oh=0,jg=0,og=0;printf("请输入n的值:\n");scanf("%d",&n);//先输入数据个数nprintf(
#includeintmain(void){intmax,min;inta,i;printf("Input10interger:");scanf("%d",&a);max=min=a;for(i=0;
悬赏分太低啦#includevoidmian(){inta,b,an[],c,d,sum-ji,sum-ou,n;a=b=c=d=sum-ji=sum-ou=0;printf("entertennum
#includeintmain(void){intn,m,max;\x05scanf("%d",n);\x05intp[n],i;\x05for(i=0,imax)//当p[0]是给max赋初值或者当
#includemain(){inti,j,N,t,k=0;intscore[100];printf("请输入整数的个数N:\n");scanf("%d",&N);printf("请输入N个整数:\n
C++版本:#includeusingnamespacestd;intmain(){intcas;while(cin>>cas){intn,p,q;intarr[1000];while(cas--){
inti,a,n;int*pl=NULL;printf("inputn:");scanf("%d",&n);if(n>0){pl=(int*)malloc(n*sizeof(int));}for(i=
#include#include#defineMAX1000intmain(){inta[MAX],i,j,n,p,q,s1,s2;p=0;q=0;s1=0;s2=0;printf("请输入要输入的值
程序不能是这样的.可以是这样的ABCDEFGHIJKLMNO一般是依次得出的.不然会很麻烦那么程序可以是这样:#includemain(){charch='A',a[50];inti,n;scanf(
#includevoidmain(){intn,i,ji=0,ou=0;//ji用来统计奇数的个数,ou用来统计偶数的个数intinput,jihe=0,ouhe=0;//jihe用来统计奇数的和,o