1. 输入整数x和a,计算并输出分段函数
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/22 22:47:09
![1. 输入整数x和a,计算并输出分段函数](/uploads/image/f/42270-6-0.jpg?t=1.+%E8%BE%93%E5%85%A5%E6%95%B4%E6%95%B0x%E5%92%8Ca%2C%E8%AE%A1%E7%AE%97%E5%B9%B6%E8%BE%93%E5%87%BA%E5%88%86%E6%AE%B5%E5%87%BD%E6%95%B0)
#includevoidmain(){inta,b;printf("Inputtwointegers:");scanf("%d%d",&a,&b);printf("和:a+b=%d\n",a+b);p
用什么语言编写再问:c语言
//#includevoidmain(){intm,n,i,min,max;printf("Pleaseinputm,n:\n");scanf("%d%d",&m,&n);min=mn?m:n;if(
if(x>0)y=(x+7)/3缺少分号if(x=0)y=0;也错了,应该if(x==0)y=0,更好的做法是if(0==x)y=0;两外,(x+7)/3是实数,将实数赋值给整型数会失去精度的.最好给
1:#includeintmain(){intnum,sum=0;while(scanf("%d",&num)==1&&num>0){sum+=num;\x09}printf("结果为%d",sum)
#includevoidmain(){inta,b;printf("pleaseinputtwonums:");scanf("%d%d",&a,&b);printf("%d%d\n",a/b,a%b)
我写了一个c语言的!#includemain(){inti,n,sum=1;scanf("%d",&n);for(i=1;i
print改成printf就可以了标准答案拿去吧除法进行的Int型的除法自己懂得#includeintmain(void){intnum1,num2;intx,y,z,k,j;printf("Ente
#include"stdio.h"intmain(){intnum[21],i,n=0,zh=0,fu=0;floatave;printf("请输入20个整数:\n");for(i=0;iscanf(
#includemain(){inta,b,c,d;printf("请输入第一个整数:");scanf("%d",&a);printf("请输入第二个整数:");scanf("%d",&b);prin
#includeintmain(void){\x09intnum,i,j,k,sum;\x09printf("输入一个三位整数!\n");\x09scanf("%d",&num);\x09i=num%
1.编译不通过数组定义时,不能使用变量,即使变量已赋值,所以inta[n];是错的解决方法,你可以直接定义一个大的数组,比如inta[100],然后再用n限制输入的个数2.数组下标是从0~n-1,所以
usingSystem;usingSystem.Collections.Generic;usingSystem.Linq;usingSystem.Text;namespaceCompare_Numbe
Dimi1AsIntegerDimi2AsIntegerDimi3AsIntegeri1=Val(InputBox("请输入第一个整数"))i2=Val(InputBox("请输入第二个整数"))i3
#include"stdio.h"#include"time.h"main(){inta[100],i,t,x,k=0;intm=1,n=100;printf("该数组元素有:\n");srand((
importjava.util.Scanner;publicclassTest20010{publicstaticvoidmain(Stringargs[]){\x05intnum1,num2;\x0
#includevoidmain(){inta,b,c,d;printf("Pleaseinput3numbers,example,[1,2,3]:\n");scanf("%d,%d,%d",&a,&
inti,geshu=0,sum=0,a[100],aver;scanf("%d",&a[i]);for(i=0;i
#include#include#includeintmain(void){intn=0,sum=0;int*nums;printf("请输入整数个数:\n");scanf("%d",&n);nums