已知x-3y=0,求2x=y除以x的平方-2xy=y的平方乘以[x-y]
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你的问题可能有错误,如果“求代数式x²-2xy-5y²除x²+2xy=5y²的值”中的“=”为“-”的话解题过程如下:∵x²-xy-2y²=
(2x+y)/(x^2-2xy+y^2)X(x-y)=(2x+y)/(x-y)²*(x-y)=(2x+y)/(x-y)x-3y=0,x=3y(2x+y)/(x-y)=(6y+y)/(3y-y
2x-3y=0(1)3x-y-1=0(2)由(2)得y=3x-1(3)把y=3x-1代入(1)得2x-9x+3=0∴x=3/7把x=3/7代入(3)得y=2/7∴x=3/7y=2/7
75=(2x+3y)(3x+2y) =6x^2+13xy+6y^2 =6(x+y)^2+xy>=24xy+xy=25xyxy<=3x+y>=2vxy=2v3最小值2v3再问:6(x+y)^2+xy
括号应该成对,还有一个括号在哪里?能不能把你的叙述用数学的语言表达出来?
8^x/2^y=2^3x/2^y=2^(3x-y)=2^(-5)=1/32
[(x的平方+y的平方)-(x-y)的平方+2y(x-y)]/4y=(x^2+y^2-x^2+2xy-y^2+2xy-2y^2)/4y=(2x-y)/2=4022/2=2011
4x-2y=0→y=2x,把所有的y都用2x替代.结果是-1/7
X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1
2x=2-3yx>0则2x>0所以2-3y>0y
因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6
3x^2+xy-2y^2=0推出(3x-2y)(x+y)=0推出x=-y或x=(2/3)y{(x+y)/(x-y)+4xy/(y^2-x^2)}/{(x+3y)*(x-y)}/x^2-9y^2推出:{
2y=x-3带入[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]/4x=[(3x+x-3)(3X-x+3)-(x+x-3)(5x+3-x)]/4x=(8x2-6x=12x-9-8x2=12
{(x的平方+y的平方)-(x的平方-y的平方)+2y(x-y)}除4y=(2y^2+2y(x-y)/(4y)=2xy/(4y)=x/2
2x+y/x^2-2xy+y^2)*(x-y)=2x+y/(x-y)^2*(x-y)=2x+y/x-yx-3y=0.x=3y将x=3y带入2x+y/x-y=6y+y/3y-y=7/2(二分之七)
|x|=5|y|=2x大于0,y大于0所以:x=5y=2所以x-y=3x÷y=2.5
2x+y+3=xy,①若x=1,则y不存在,此时5x+4y无最值;②若x≠1,则y=(2x+3)/(x-1),M=5x+4y=5x+(8x+12)/(x-1)=(5x²+3x+12)/(x-
∵x^2-3y^2=2xy∴x^2-2xy-3y^2=0∴(x+y)(x-3y)=0∵x>0,y>0∴x-3y=0∴x=3y∴x+2y/x-y=3y+2y/3y-y=2y+2/3或=2/3(x+1)如
10的4次方原式*2得10X-6Y=410的10X次方除以10的6Y次方为:10的(10X-6Y)次方固结果为:10的4次方
绝对值项恒非负,两绝对值项之和=0,两绝对值项分别=03x-y=0(1)x+y=0(2)(1)+(2)4x=0x=0,代入(2)y=-x=0(x-y)/(xy)无意义,因此题目错了.