已知x y=-8,xy=8,求y
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题目写错应该是求(6xy+7y)+[8x-(5xy-y+6x)](6xy+7y)+[8x-(5xy-y+6x)]=6xy+7y+8x-5xy+y-6x=xy+2x+8y=xy+2(x+4y)=5+2×
一、x²y-xy²-x+y=56xy(x-y)-(x-y)=56(xy-1)(x-y)=56将xy=8代入:7(x-y)=56x-y=8①又x²+y²=(x-y
x-xy=8(1)xy-y=-9(2)则有(1)-(2):X-XY-XY+Y=X+Y-2XY=8-(-9)=17
yx+xy=xyx+xyy=xy(x+y)xy,∵x+y=8,xy=6,∴原式=6×86=463.
(5X-4Y-3XY)-(8X-Y+2XY)=-(3X+3Y)-5XY=-3*6+4*5=2
-xy(x^2y^5-xy^3-y)=-(xy^2)^3+(xy^2)^2+xy^2=-(-2)^3+4-2=8+4-2=10
由于xy除以x+y=2故xy=2(x+y)将这代入8x-5xy+8y除以-x+3xy-y化简得其中的(x+y)会相互约去故8x-5xy+8y除以-x+3xy-y=-2/5希望这个能帮到你over~
x^2+2xy+y^2=x²+xy+xy+y²=(x²+xy)+(xy+y²)=8+3=11x²-y²=x²+xy-xy-y
解题思路:本题是求整式的值,注意一定要先化简,再求值。化简就是先去括号,在合并同类项。解题过程:解:(6xy+7y)+[8x-(5xy-y+6x)]=(6xy+7y)+[8x-5xy+y-6x]=6x
1/x+1/y=(x+y)/xy=8x+y=8xy2x-3xy+2y/x+2xy+y=[2(x+y)-3xy]/[(x+y)+2xy]=(16xy-3xy)/(8xy+2xy)=13xy/10xy=1
原式=6xy+7y+8x-5xy+y-6x=xy+2x+8y=xy+2(x+4y)=···再问:还有些题哈……
原式=6xy+7y+8x-5xy+y-6x=xy+8y+2x=xy+2(x+4y)=5+2×(-1)=3
6xy+7y)+【8x-(5xy-y+6x)】=xy+8y+2x=xy+2(4y+x)=5-2=3
原式=6xy+7y+8x-5xy+y-6x=xy+2(4y+x)=5-2=3
(6xy+7y)+[8x-(5xy-y+6x)]=6xy+7y+(8x-5xy+y-6x)=6xy+7y+8x-5xy+y-6x=(6xy-5xy)+(7y+y)+(8x-6x)=xy+8y+2x=x
6xy+7y+[8x-5xy+y-6x]=6xy+7y+8x-5xy+y-6x=(6xy-5xy)+(7y+y)+(8x-6x)=xy+8y+2x=xy+2(4y+x)=5-2=3再问:请问x=?y=
1、已知2x²+xy=10,3y²+2xy=6,求4x²+8xy+9y²的值为?分析:通过观察,可以把8xy拆成2xy+6xy,分别于剩余的两项组合,并提取公因
将xy=8代入x平方y-8xy平方-x+y=56得8x-8y-x+y=56x-y=8x平方+y平方=(x-y)^2+2xy=8^2+2*8=64+16=80
那9是负的吗~如果不是等于负1,如果是负九等于十七~用第一个等式减第二个等式
原式=-xy²(x²y^4-xy²-1)∵xy²=-2原式=2((-2)²-(-2)-1)=10