已知2x 5y 4z=6 3x y-7z=-4求x y-z

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已知2x 5y 4z=6 3x y-7z=-4求x y-z
已知x-xy=8,xy-y=-9,求x+y-2xy的值

x-xy=8(1)xy-y=-9(2)则有(1)-(2):X-XY-XY+Y=X+Y-2XY=8-(-9)=17

已知A=5x²-3xy²+2xy,B=7xy²-2xy+x²y

A-2B=5x²-3xy²+2xy-2(7xy²-2xy+x²y)=5x²-3xy²+2xy-14xy²+4xy-2x²

已知x2-xy=7,2xy+y2=4,则代数式x2+xy+y2的值是___.

∵x2-xy=7,2xy+y2=4,∴原式=(x2-xy)+(2xy+y2)=7+4=11,故答案为:11

已知xy^2=-2,求-xy(x^2y^5-xy^3-y)的值.

-xy(x^2y^5-xy^3-y)=-(xy^2)^3+(xy^2)^2+xy^2=-(-2)^3+4-2=8+4-2=10

已知x+y=4,xy=2,求代数式2(3x+2xy)+(2xy+3x+2y)-(4xy-7y)的值

原式=6x+4xy+2xy+3x+2y-4xy+7y=9x+9y+2xy=9(x+y)+2xy=9×4+2×2=36+4=40

已知x2+xy=-3,xy+y2=7,试求:x2+2xy+y2的值.

∵x2+xy=-3,xy+y2=7,∴(x2+xy)+(xy+y2)=-3+7=4,即x2+2xy+y2=4.

已知:xy+x=-1,xy-y=-2.

(1)∵xy+x=-1①,xy-y=-2②,∴①-②得x+y=1;(2)先把xy+x=-1,xy-y=-2的值代入代数式,得原式=-x-[2y-1+3x]+2[x+4]=-x-2y+1-3x+2x+8

已知x:y=3:2,求(x²+3xy)/(xy+2xy)

答案是3/2你是不是把分母打错了教你个方法因为上下是齐次的直接令x=3y=2带入就行

已知X+y=6,xy=7 求x^2y+xy^2=

x^2y+xy^2=xy(x+y)=7x6=42再问:��(x+1)^2=13��x^2+2x+3=再答:x^2+2x+3=(x+1)^2+2=13+2=15

已知xx+xy=1,xy-yy=-4,则xx+2xy-yy=

xx+2xy-yy=-3两式相加即可

已知xy^2=-2求xy(2x^3y^7+5x^2y

最简单的方法就是用特殊值,令x=-2,y=1然后代入所求表达式,求出其值.为-8;另外此内题的另一个解法是变化所求表达式,使它变成关于xy^2的表达式.

由已知x+y=-2,xy=3那么2(x+xy)-[(xy-3y)-x]-(-xy)等于多少?

2(x+xy)-[(xy-3y)-x]-(-xy)=2x+2xy-xy+3y+x+xy=3x+3y+2xy=3(x+y)+2xy=3*(-2)+2*3=0

已知a=5x的平方y-3xy的平方+4xy,b=7xy的平方-2xy+x的平方y.

a-2b=(5x²y-3xy²+4xy)-2(7xy²-2xy+x²y)=5x²y-3xy²+4xy-14xy²+4xy-2x&#

已知x-y=4xy,则2x+3xy-2yx-2xy-y

∵x-y=4xy,∴2x+3xy-2yx-2xy-y=2(x-y)+3xyx-y-2xy=8xy+3xy4xy-2xy=112.故答案为:112.

已知xy为正整数,3xy=2x+3y+5.求xy=?

3xy=2x+3y+5(3y-2)(x-1)=7所以3y-2=7x-1=1得y=3x=2xy=6或3y-2=1x-1=7得y=1x=6xy=6所以xy=6

已知A=8x^2y-6xy^2-3xy,B=7xy^2-2xy+5x^2y,

∵A=8x²y-6xy²-3xy,B=7xy²-2xy+5x²y ∴C=3(A+B)  =3(8x²y-6xy²-3xy+7xy²

已知A=5x^2y-3xy^2+4xy,B=7xy^2-2xy+x^2y.

已知A=5x^2y-3xy^2+4xy,B=7xy^2-2xy+x^2y.(1)求A-2B的值A-2B=5x^2y-3xy^2+4xy-2*(7xy^2-2xy+x^2y)=5x^2y-3xy^2+4

已知x²-7xy+12y²=0求x²-xy+y²/2xy的值

x²-7xy+12y²=0(x-3y)(x-4y)=0x1=3yx2=4yx=3y时原式=9y²-3y²+y²/6y²=7/6x=4y时原式

已知xy^2=-2 求-xy(x^2y^5-xy^3-y)

原式=-xy²(x²y^4-xy²-1)∵xy²=-2原式=2((-2)²-(-2)-1)=10