已知2x 3y 4z=10,求x2 y2 z2
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![已知2x 3y 4z=10,求x2 y2 z2](/uploads/image/f/4205106-18-6.jpg?t=%E5%B7%B2%E7%9F%A52x+3y+4z%3D10%2C%E6%B1%82x2+y2+z2)
∵x2+x+3=0,∴x2+x=-3,x5+3x4+2x3+2x2-10x=x3(x2+x)+2x4+2x3+2x2-10x=-3x3+2x4+2x3+2x2-10x=2x4-x3+2x2-10x=2
x2+3x2+1=0中的3x2表示什么?再问:已知X2+3X+1=0,求X2+1/X2的值?得数是7。求过程?我打的是X的平方。怎么会出X2、再答:答:因为x≠0,两边都除以x得:x+1/x=-3,两
(x-1)^2+(y-1)^2=1令x-1=sinay-1=cosa则x=1+sina,y=1+cosax^2+y^2=1+2sina+(sina)^2+1+2cosa+(cosa)^2=3+2(si
应该是求-x³+2x²+2008x²=x+1所以x³=x²*x=(x+1)x=x²+x=(x+1)+x=2x+1所以-x³+2x&
由条件左右除以x,得x+1/x=3平方得:x2+1/x2+2=9所以x2+1/x2—2=5所求值为根号5
x^2+1/x^2=(x+1/x)^2-2=2
∵3x2-2x=2,∴32x2-x+1=12(3x2-2x)+1=1+1=2.
设t=√x^2+2x>=2∴t>=√6y=t+3/t由对勾函数的性质,t>=√3时单调递增所以当t=√6时,函数取最小值最小值为(3√6)/2再问:好难哦,你到底怎样想的?再答:关键是要去掉根号,去掉
X^2-5x=14->x=-2或x=72x^2-x-2x+1-[x^2+2x+1]+1=x^2-5x+1=15
(1)函数y=2x+2−x2的定义域为R,∵2x+2−x≥22x•2−x=2,当且仅当x=0时取等号.∴y≥1,因此函数的值域为:[1,+∞).(2)∵f(-x)=2−x+2x2=f(x),定义域为R
(x²+y²)²+(x²+y²)-6-6=0(x²+y²)²+(x²+y²)-12=0(x²
已知x²+x+1=0那么x⁴+2x³-x²-2x+2014=x²(x²+x+1)+x(x²+x+1)-3(x²+x+1
x²-2x+y²+6y+10=0,变换得(x-1)²+(y+3)²=0,∴x=1,y=-3∴(x2-2xy)/(xy+y2)=(1²-2*(-3))/
条件变换:(x-3)^2+(y+1)^2=0即:y+1=0x-3=0所以:立方根号x2-y2=2
设t=x2+y2(t大于等于0)则t(t+2)-3=0(t+3)(t-1)=0t=-3(舍去)或t=1所以,x2+y2=1
即(x²+4x+4)+(y²-6y+9)=0(x+2)²+(y-3)²=0所以x+2=y-3=0x=-2,y=3所以原式=(4+4)/(4+27)=8/31
可设x²+y²=t.则t(t-1)=2.===>t²-t-2=0.===>(t-2)(t+1)=0.===>t=2.即x²+y²=2.
你好x²+3x-1=0两边同除以xx+3-1/x=0x-1/x=-3两边平方得x²+1/x²-2=9x²+1/x²=11x²+1/x
3x2+2y2-6x=0x2+y2=1/2(6x-x2)=9/2-1/2(x2-6x+9)=9/2-2-1/2(x-3)2当x=3时,Z最大=4.5