9(m-n)-4m n分解因式
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/15 16:18:14
所谓分解因式,就是把式子改写成若干个式子相乘的乘积.mn²+6mn+9m=m×(n+3)²
m(m+n)²-4mn²=m[(m+n)²-4n²]=m[(m+n)+2n][(m+n)-2n]=m(m+3n)(m-n)
m+m^2-mn^2+2m^2n=m(1+m+2mn-n^2)
原式=m²+5mn-3mn-15n²=m(m+5n)-3n(m+5n)=(m+5n)(m-3n)再问:还有道题。分解因式(a-b)的平方-(a-b)-2,要详细过程再答:令x=a-
原式=4m^2+8mn-4n^2-4n^2+3n^2=(2m+2n)^2-n^2=(2m+2n+n)(2m+2n-n)=(2m+3n)(2m+n)
原式=3²(m-n)²-5²(m+n)² =[3(m-n)]²-[5(m+n)]² =[3(m-n)-5(m+n)]*[3(m-n)+5
m-n-mn+1,=(m-mn)+(1-n),=m(1-n)+(1-n),=(m+1)(1-n).
2㎡—mn+2m+n—n²=2m²-(n-2)m+n(1-n)=(2m+n)(m+(1-n))=(2m+n)(m-n+1)此题如仍有疑问,欢迎追问!再问:2步到3步再详细一点再答:
2m^2n^2-2n^2+(mn-1)(m-1)^2=2n^2(m^2-1)+(mn-1)(m-1)^2=2n^2(m-1)(m+1)+(mn-1)(m-1)^2=(m-1)[2n^2(m+1)+(m
1:2m²n-3mn²=mn(2m-3n)……………………(√)2:-2a²-4a=-2(a+2)…………………………(×) -2a²-4a=-2a(a+2)
m^2n-2mn^2+mn=mn(m-2n+1)
mn+m^2n^2+m^2n+mn^2=m^2n(n+1)+mn(n+1)=mn(n+1)(m+1)或:mn+m^2n^2+m^2n+mn^2=mn(mn+m+n+1)=mn(n+1)(m+1)
[2(3m+2n)]^2-[3(2m+3n)]^2=[2(3m+2n)+3(2m+3n)][2(3m+2n)-3(2m+3n)]=(12m+13n)(-5n)
m平方-4mn+3n平方=(m²-4mn+4n²)-n²=(m-2n)²-n²=(m-2n+n)(m-2n-n)=(m-n)(m-3n)x平方-4x-
-4m^2n^3+12m^3n^2-2mn=2mn(6m²n-2mn²-1)不明白,可以追问如有帮助,记得采纳如追加其它问题,采纳本题后点击想我求助,谢谢祝学习进步!
m²+2n-mn-2m=m(m-n)-(2m-2n)=m(m-n)-2(m-n)(m-n)(m-2)
1原式=(3(m-n)-2)²2原方程可化为x²-4x+4=4x-8x²-8x+12=0(x-2)*(x-6)=0x=2或63第三题看清楚题目
-m²+4mn-4n²=-(m²-4mn+4n²)=-(m-2n)²
m²+4mn+4n²=(m+2n)²
(m-n)²—9(m+n)²=【(m-n)-3(m+n)】【(m-n)+3(m+n)】=(-2m-4n)(4m+2n)=-4(m+2n)(2m+n)