5-x x-4 1 4-x=1

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5-x x-4 1 4-x=1
已知xx-2x-1=0,求xxxx-xxx-5xx-7x+5的值拜托各位大神

xxxx-xxx-5xx-7x+5=(xx-2x-1)(xx+x-2)-10x+3=-10x+3由xx-2x-1=0得x=1±√2所以,xxxx-xxx-7x+5=-7±10√2

已知X*X-5X+1=0,求X*X+1/XX的值

∵x²-5x+1=0两边同时除以x得∴x-5+1/x=0∴x+1/x=5两边同时平方得∴x²+2+1/x²=25∴x²+1/x²=25-2∴x

x+xx+xxx=xxxx

随便给个答案3+84+975=1062

若已知X+1/x=5则X²/X²xX²+X²+1等于几

到底是x+(1/x)=5还是(x+1)/x=5?后面也一样,乘号能省不省还没有括号,望补充再问:是X+(1/X)=5再答:X²/X²xX²+X²+1是(X

已知x+1/x=3,求(xx)/(xxxx+xx+1)的值

(xx)/(xxxx+xx+1)=x^2/(x^4+x^2+1)=1/x^2+1+x^2=x^2+1/x^2+2-1=(x+1/x)^2-1=3^2-1=8

5x-1=4x 求XX=多少

5x-1=4x5x-4x=1x=1

已知:3x=xx-x+1求(xxxx+xx+1)分之xx

由已知方程可得:X^2=4X-1然后将分式中的X平方换成4X-1X的四次方换成X平方的平方再整理再将整理后的X平方继续换成4X-1最后化简:分子为4X-1分母为15(4X-1)得答案1/15这个题主要

解方程1/(xx+x)+1/(xx+3x+2)+1/(xx+5x+6)+1/(xx+7x+12)+1/(xx+9x+20

方程左边1/(xx+x)+1/(xx+3x+2)+1/(xx+5x+6)+1/(xx+7x+12)+1/(xx+9x+20)对分母因式分解得1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(

函数f(x)=xx+1

根据题意,有x≥0,则f(x)=xx+1=1x+1x而x+1x≥ 2则f(x)≤12,故答案为12.

小数奥数网xx(x +1)x(x+ 2)x(x +3)=360怎样算?

x和乘号混淆了360=2X2X2X3X3X52X2=42X3=636=3X4X5X6所以x=3

已知xx+x-1=0,求:xx+1/xx,xxxx+1/xxxx

x²-1=-x两边除以xx-1/x=1两边平方x²-2+1/x²=1x²+1/x²=3x²+1/x²=3两边平方x^4+2+1/x

已知x/(xx+x+1)=a,求xx/(xxxx+xx+1)的值

x/(xx+x+1)=a分子分母除以x,1/(x+1+1/x)=a,x+1/x=1/a-1,两边平方xx+2+1/xx=(1/a-1)^2xx+1/xx=(1/a-1)^2-2xx/(xxxx+xx+

已知xx-5x+1=0,求xxxx+1/xx的值

x^2-5x+1=0方程两边同除以xx-5+1/x=0x+1/x=5(x^4+1)/x^2=x^2+1/x^2=(x+1/x)^2-2=5^2-2=25-2=23方可以用“^”表示再问:(x^4+1)

已知x(x+1)-(xx+y)=3,求(xx+yy)/2-xy的值

x^2+x-x^2-y=3x-y=3(x-y)^2=9x^2+y^2-2xy=9(x^2+y^2)/2-xy=9/2

XXX*XX=XX*XX=3624,X内填写1-9,数字不能重复

无解!分解质因数:3624=2*2*2*3*151因而必定有一个乘数大于等于151与右边的XX*XX中两个乘数都是两位数相矛盾,所以不可能

x(x+1)-(xx+y)=-3,求(xx+yy)/2-xy的值

x(x+1)-(xx+y)=-3x^2+x-x^2-y=-3x-y=-3(xx+yy)/2-xy=(x^2+y^2-2xy)/2=(x-y)^2/2=(-3)^2/2=9/2再问:是对的吧!再答:当然

帮我做做 初三的题目吧! 2xx-5x+3=0 xx-3x-1=0 5xx=2x+1 2(x+3)(x+3)=3x+19

这题目是4方程?xx是x的平方吗?若是的话1.2x方-5x+3=0(2x-3)(x-1)=0x1=2/3(二分之三)x2=1十字相乘配下就出来了2..x方-3x-1=0公式法△=b方-4ac=9+4=