在1,2,7,8,9,11,15中[]是[]的倍数,[]是[]的因数

用分类讨论的方法吧,先考虑末位为0,在考虑末位为2（末位为4,6,8的情况都与2的相同）,就可以了现在比较晚了,我明天再帮你、、能等会儿吗再问：好的，明天中午再答：我正在写、等一下~答案应该是5760

1OnMay12in20123intheweekend4onMonday5at4:306playtheguitar7up8gotobed9home10arrivedattheschool

9无论加还是减8都为奇数加或减7为偶数偶数加减偶数6为偶数偶数加减奇数5为奇数奇数加减偶数4为奇数奇数加减奇数3为偶数偶数加减偶数2为偶数偶数加减奇数1为奇数因为20不是奇数所以无解

inJanuaryonJanuary2rdonApril12thonMondayat8o'clockthismorninginDecemberinOctobertwelvemonthsyearmyfa

马克,一会做,这题有意思再问：快一点哦！再答：61行，3列。第一列的规律是1+2+3+...n,所有，第63行第一列是2016，倒退可得

1、At10:30inthemorning2、At8:45thisevening3、Oneandahalfhours4、Nextmarch5、Thedaybeforeyesterday6、OnSept

1/9=5/45.1/3=5/15.所以括号中填16到44之和为870.

如果是1790的话,读せんななひゃくきゅうじゅう

1.ninehundredandeighty-sevenmillion,sixhundredandfifty-fourthousand,threehundredandtwenty-one2.by...

1Sittinginfrontofme2inthebusfrontthreeinbetweenherandme4inoppositethesupermarket5ontheplatform620,00

1+2+3+4+5-6+7+8+9-10-11-121+2+3-4-5-6-7-8-9+10+11+12

753428961614957382892163457138245796975316248426789135289574613367891524541632879

1,设7点x分（x-35)*12=x分针转一圈,时针转1/12圈x=35*12/11x=38.182,夹角60度,1/6圈有两种可能一、（x+10-40)*12=xx=360/11二、(x-10-40

1.postoffice2.onCenterStreet3.payphone4.acrossfromthebank5.between...and...6.near或nextto7.intheneigh

1、在3:45atthreeforty-fiveataquartertofour2、在4:15atfourfifteenataquarterpastfour3、在5点atfive(o'clock)4、

2009是第1005个数1-44组共990个数所以2009在第45组

11+10-9-8+7-6+5-4-3-2=1,11+10+9-8-7-6-5-4+3-2=1,

=$A$1*100+INDEX($B$1:$B$10,INT((ROW()-1)/10)+1)*10+INDEX($C$1:$C$10,MOD(ROW()-1,10)+1)

InMayInOctober2008Inthespring\summer\autumn\winterInAugust12InFebruary25,2008InMother'sDayInTeacher'

1.inthefrontof2.infrontof3.amoung……4.nearto5.aroundtheshop8.beween……9.inthemorning10.inarainyafterno