因式分解x2(a b)2-2xy(a-b)2 y2(a-b)2
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![因式分解x2(a b)2-2xy(a-b)2 y2(a-b)2](/uploads/image/f/3138408-0-8.jpg?t=%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3x2%28a+b%292-2xy%28a-b%292+y2%28a-b%292)
25(x²+2xy+y²)-9(x²-2xy+y²)=[5(x+y)]²-[3(x-y)]²=[5(x+y)+3(x-y)][5(x+y)-
x²+y-xy-x=﹙x²-xy﹚+﹙y-x﹚=x﹙x-y﹚-﹙x-y﹚=﹙x-y﹚﹙x-1﹚
(1)已经分解了,不能再分了(2)(2bx-ay)(2ax-by)
3xy(x²y-xy²+xy)-xy²(2x²-3xy+2x)=3x³y²-3x²y³+3x²y²-
x^2+xy-2y^2-x+7y-6=(x+2y)(x-y)-x+7y-6x+2y-3Xx-y2十字相乘得:2(x+2y)-3(x-y)=-x+7y是一次项所以原式=(x+2y-3)(x-y+2)
x2+2xy+y2+4x+4y+4=(x+y)2+4(x+y)+4=(x+y+2)2.故答案为:(x+y+2)2.
原式=25(x+y)²-9(x-y)²=[5(x+y)+3(x-y)][5(x+y)-3(x-y)]=(8x+2y)(2x+8y)=4(4x+y)(x+4y)
十字相乘法原式=(2x-3y)(x+y)
-xy^2+2xy-x=-x(y^2-2y+1)=-x(y-1)^2如果本题有什么不明白可以追问,如果满意请点击“选为满意答案”
十字相乘学了没啊?这题直接十字相乘就可以啦!x2-x-21-211(x-2)(x+1)∴x2-x-2=(x-2)(x+1)
原式=(x2-2xy+y2)-z2=(x-y)2-z2=(x-y+z)(x-y-z).
x3+(y-1)x2-2xy-y2=x^3+x^2y-x^2-2xy-y^2=x^2(x+y)-(x+y)^2=(x+y)(x^2-x-y)
x2-9a2+12a-4=x2-[(3a)2-2*3a*2+4]=x2-(3a-2)^2=(x+3a-2)(x-3a+2)x2y+3xy2-x-3y=xy(x+3y)-(x+3y)=(xy-1)(x+
x2y2+3xy+2=(xy)^2+3xy+2=(xy+2)(xy+1)很高兴能帮助您~!
很难,因为不能变成系数为整数甚至分数的因式积.
=[x+(3-√5)/2*y][x-(3-√5)/2*y]有点牵强,但这是唯一的答案了
您好:x2+x-2=(x+2)(x-1)如果本题有什么不明白可以追问,如果满意请点击右下角“采纳为满意回答”如果有其他问题请采纳本题后另发点击向我求助,答题不易,请谅解,谢谢.祝学习进步!O(∩_∩)
2x²+xy-3y²+x+4y-1=2×x×x+x×y-3×y×y+x+4×y-1=x×2x+x×y-y×3y+x×1+y×4-1=x×(2x+y+1)-y×(3y+4)-1再问:
首先,X^2-XY+2Y^2=(X-2Y)(X+Y)所以,设x^2-xy-2y^2-x+5y-2可分解成(X-2Y+A)(X+Y+B)则展开有X的一次项=A+B=-1Y的一次项有A-2B=5连列成方程
x^3+x^2+xy-xy^2=x(x^2+x+y-y^2)=x(x^2-y^2+x+y)=x[(x+y)(x-y)+(x+y)]=x(x+y)(x-y+1)