4-4x+x²分之2x-6÷﹙x+3﹚×3-x分之x²+x-6

原式=[(2x-6)/(x^2-4x+4)]/(x+3)*(x^2+x-6)/(3-x)=[2(x-3)/(x-2)^2]/(x+3)*(x+3)(x-2)/(3-x)=-2/(x-2)

原式=[(x²+2x)/(x²+4x+4)]÷[(2x²-8)/(3x+6)]÷[1/(x²-4)]=[x(x+2)/(x+2)²]÷{2(x+2)(

(x+2分之2x-x-2分之x)÷x²-4分之x（x+2x/2-x-x/2）÷x²-x/4=x/2÷x²-x/4=1/2x-x/4很高兴为您解答,祝你学习进步!有不明白的

x^2-x-6分解因式得(x+2)(x-3)x^2-4分解因式得(x-2)(x+2)故(x^2-x-6分之x^2-4+x-3分之x+2)=(x-2)/(x-3)+(x+2)/(x-3)=2x/(x-3

原式=(x^2+3x)/(x^2+x-6)-(x+2)/(x^2-4)=x(x+3)/(x+3)*(x-2)-(x+2)/(x+2)*(x-2)=x/(x-2)-1/(x-2)=(x-1)/(x-2)

小括号内先通分：分母为x平方-4,分子为3x平方+6x,另一个是x平方-2x化简：{x²-4分之2x²+8x}÷x²-4分之2x结果=x+4

你写的看不懂分子分母的代数式用括号括起来否则分不出来先通分【（（x-2）(x+2)-x(x-1)）/x(x+2)(x+2)】(x+2)/(x-4)=(x-4)/x(x+2)(x-4)=1/x(x+2)

题目表达不清楚

(x-1)/3-(x+2)/6=(4-x)/2等式两边同乘6得：2(x-1)-(x+2)=3(4-x)去括号：2x-2-x-2=12-3x移项：4x=16x=4

[(x-2)分之3x-(x+2)分之x]乘x分之(x²-4)=[(x-2)分之3x]乘x分之(x²-4)-[(x+2)分之x]乘x分之(x²-4)=3(x+2)-(x-2

=[(x+2)(x-2)/(x-3)(x+2)+(x+2)/(x-3)]×(x-3)/(x+1)=[(x-2)/(x-3)+(x+2)/(x-3)]×(x-3)/(x+1)=2x/(x-3)×(x-3

4-4x+x^2分之2x-6除以（x+3)乘以3-x分之x^2+x-6=2(x-3)/(x-2)²×1/(x+3)×(x+3)(x-2)/(3-x)=-2/(x-2)

解原式=3(2-x)/3(x-4)(x+2)+(x+4)(x-4)/3(x+2)(x-4)=(6-3x)/3(x-4)(x+2)+(x²-16)/3(x+2)(x-4)=(6-3x+x

4分之5X-X+3=3分之2X-7-6分之X-25X/4-X+3=(2X–7)/3-(X-2)/615X-12X+36=4(2X–7)-2(X-2)3X+36=6X–243x=60X=20

本人一次只回答一个算了吧或者你分开提问x/(x+2)=x/(x-1)两边乘(x+2)(x-1)x²-x=x²+2x3x=0x=0经检验,x=0是方程的解

x+2分之1+x^2-4分之x+6-x^-4x+4分之2x+1=x-2/x^2-4+x+6/x^2-4-(2x+1/x^-4x+4)=2x+4/x^2-4--(2x+1/x^-4x+4)=2/x--2

（x-2分之x减x+2分之x）=(x-2)(x+2)分之x(x+2)-x(x-2)乘4x分之2-x=(x-2)(x+2)分之4x乘4x分之2-x=-x-2

[（x+2)/x-(x-1)/(x-2)]÷（x-4)/x=[1+2/x-1-1/(x-2)]×x/(x-4)=(x-4)/x(x-2)×x/(x-4)=1/(x-2)=1/(3-2)=1这是我在静心

X=4原式=(X-1)/(X-2)-(X-2)/(X-3)=(X-4)/(X-5)-(X-5)/(X-6)左边通分=[X^2-4X+3-X^2+4X-4]/[(X-2)(X-3)]=-1/[(X-2)