2X减X加1的和除以2
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![2X减X加1的和除以2](/uploads/image/f/262792-64-2.jpg?t=2X%E5%87%8FX%E5%8A%A01%E7%9A%84%E5%92%8C%E9%99%A4%E4%BB%A52)
1楼最后算错了引用一下:1/(x+1)-1/(x²-1)÷(x+1)/(x²-2x+1)=1/(x+1)-1/(x+1)(x-1)×(x-1)(x-1)/(x+1)=1/(x+1)
2X除以7加4分之1X的和除以5X除以7加3X除以4=(2X/7+X/4)/(5X/7+3X/4)=(8X+7X)/(20X+21X)=15/41
你是想问a=?a=-7
X-(X-1)/2=1+(X+2)/5两边乘以1010X-5(X-1)=10+2(X+2)3X=9X=3
不算这里分母有未知数,所以不是整式所以不是多项式
x=-1/3
x=(m+1)/4,y=(m-1)/2m=4x-1,m=2y+14x-1=2y+1y=2x-1
题目应该是:x/(x^2-x-1)=7,求:x^2/(x^4+x^2+1)=?由题知,x≠0,所以已知两边同时取倒数,得(x^2-x-1)/x=1/7x-1-/x=1/7x-1/x=8/7上式两边同时
你的题是[(x-2)/(x+2)]-1=3/(x^2-4)等式前面通分得:(x-2)/(x+2)-(x+2)/(x+2)=3/(x^2-4)化简:-4/(x+2)=3/(x^2-4)3x+6=-4x^
x的平方减2x加1除以x的平方减1的差加x减1除以x的平方加x的和减x原式=(x-1)²÷(x²-1)+(x-1)÷(x²+x)-x=(x-1)/(x+1)+(x-1)/
是(x-1)/(x-2+1)=3吗x-1=3x-3无解
2x-(x+1)÷2=2+(x+1)÷22x-0.5x-0.5=2+0.5x+0.51.5x-0.5=0.5x+2.51.5x-0.5x=2.5+0.5x=3
x/(x-1)+1=(2x-1)/x[x²+x(x-1)]/x(x-1)=(2x-1)(x-1)/x(x-1)当x(x-1)≠02x²-x=(2x-1)(x-1)x=x-1无解
x²-x-1=0,﹙x∧4+2x+1﹚/x²=∵x²-x-1=0,∴x1=(1+√5)/2,x2=(1-√5)/2.x²=x+1.﹙x∧4+2x+1﹚/x
(2x+1)/3-(x+1)/6=22(2x+1)-(x+1)=124x+2-x-1=123x=12-1x=11/3
解题思路:去分母进行求解解题过程:答案见附件最终答案:略
(x^2-x-2)/(x+1)=(x-2)(x+1)/(x+1)=x-2
7/(x²+x)+4/(x²-x)=6/(x²-1)都乘以x(x+1)(x-1)得:7(x-1)+4(x+1)=6x解得:x=3/5
解:x/(x-2)÷[2+x-4/(2-x)]=x/(x-2)÷[(x+2)(x-2)+4]/(x-2)=x/(x-2)÷x^2/(x-2)=x/(x-2)*(x-2)/x^2=1/x