化简sin(π 3-3X)cos(π 3 3X)-cos(π 6-3X)

-cosx

2sin^2[(π/4)+x]+根号3（sin^x-cos^x）-1=-(1-2sin^2[(π/4)+x)-√3cos2x=-cos(π/2+2x)-√3cos2x=sin2x-√3cos2x=2[

原式=sinx(-sinx)(-cotx)/(-cosx)(-cosx)tanx=sin^2xcos^2x/sin2^xcos^2x=1

(sinα-cosα)²+sin4α/2cos2α=1-2sinαcosα+2sin2αcos2α/2cos2α=1-sin2α+sin2α=1sin²x+sin²(x+

∵cosπ/6=√3/2sinπ/6=1/2cosπ/6sinx+sinπ/6cosx=sin(x+π/6)∴√3sinX+cosX=2(√3/2sinX+1/2cosX)=2(cosπ/6sinx+

根号3（根号3/2*cosx-1/2sinx）=根号3（sin60cosx-cos60sinx)=根号3*sin(60-x)这里注意将根号3提取出来.为什么提出根号3呢因为根号下【(3/2）^2+((

f(x)=sin(π-x)cos(3π/2+x)+sin(π+x)sin(3π/2-x)=(sinx)(sinx)+(-sinx)(-cosx)=sinx(sinx+cosx)f'(x)=cosx(s

化简求值:sin(π/4-3x)*cos(π/3-3x)-cos(π/63x)*sin(π/43x)岳莪耐你|2010-03-31我没分了!拜托!明天要交!=sin(π/4-3x)*cos(π/3-3

1、sin²(﹣x﹣π)cos(π＋x)cosx/[tan(2π＋x)cos³(﹣x－π)]＝sin²x×(﹣cosx)×cosx/[tanx×(﹣cos³x)

原式=sin（x+π/3）+√3cos（x+π/3）+2sin（x-π/3）=2[1/2sin(x+π/3)+√3/2cos(x+π/3)]+2sin(x-π/3)=2sin(x+π/3+π/6)+2

f(x)=cos(2x-π/3)-(cos^2x-sin^2x)=cos(2x-π/3)-cos2x=2sin(2x-π/6)sinπ/6=sin(2x-π/6)因为y=sinx的单减区间为[π/2+

sin^4x-sin^2xcos^2x+cos^4x=sin^4x+2sin^2xcos^2x+cos^4x-3sin^2xcos^2x=(sin^2x+cos^2x)^2-3sin^2xcos^2x

f(x)=cos(2x-π\3)+sin²x-cos²x=1/2cos2x+√3/2sin2x-cos2x=√3/2sin2x-1/2cos2x=-cos(2x+π\3)-1

3/2cosx-3/2(sinx)^2

cos(X-Y)=cosXcosY+sinXsinY原式=cos(30.）再问：能写具体点吗?谢谢了再答：原式=cos（X+30。-X）=cos(30。），按着给的那个公式看就对了

sin(x-π/3)-cos(x+π/6)+√3cosx=sinxcosπ/3-cosxsinπ/3-cosxcosπ/6+sinxsinπ/6+√3cosx=1/2*sinx-√3/2*cosx-√

y=sin²x+2sinxcosx+3cos²xy=(sin²x+cos²x)+2sinxcosx+(2cos²x-1)+1=1+sin2x+cos2

利用积化和差公式sinAcosB=(1/2)*[sin(A+B)+sin(A-B)]以及sin(-A)=-sinA的性质可得sin(x)(cos(x)+cos(3x)+cos(5x)+cos(7x))

2（√3/2sinx+1/2cosx)=2sin(x+π/6）√2*√2（√2/2sinx-√2/2cosx)=2sin(x-π/4）（3）解;2√2(1/2cosx-√3/2sinx)=2√2cos

f(x)=sin(a-3π)cos(2π-a)sin(-a+3π/2)/cos(-π-a)sin(-π-a)=sin(4π+a-3π)cosasin(3π/2-a)/cos(π+a)sin(2π-π-