函数fx=Asin(wx φ) x∈R的图像与x轴的交点
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![函数fx=Asin(wx φ) x∈R的图像与x轴的交点](/uploads/image/f/2325524-68-4.jpg?t=%E5%87%BD%E6%95%B0fx%3DAsin%28wx+%CF%86%29+x%E2%88%88R%E7%9A%84%E5%9B%BE%E5%83%8F%E4%B8%8Ex%E8%BD%B4%E7%9A%84%E4%BA%A4%E7%82%B9)
解由题知A=3T=4(π/2-(-π/2))=4π又由T=2π/w故2π/w=4π故w=1/2故f(x)=3sin(1/2x+φ)其图像过点(-π/2,3)知3sin(1/2x(-π/2)+φ)=3即
已知函数f(x)=Asin(ωx+φ)图像如图求f(x).答:f(x)=2sin(150°x+90°)由图可见,A=2f(x)=2sin(ωx+φ)f(2)=2sin(2ω+φ)=√3-->2ω+φ=
函数y=Asin(wx+φ)由2kπ-π/2
A=22sinφ=√3φ=π/3w*(5π/6)+π/3=π或w(5π/6)+π/3=2πw=4/5w=2f(x)=2sin【(4/5)x+π/3】f(x)=2sin(2x+π/3)-π/2
(1)1/4T=π/6T=2π/3w=2π/T=3A=2所以现在方程为f(x)=2sin(3x+φ)将(π/12,2)代入π/4+φ=π/2φ=π/4方程为f(x)=2sin(3x+π/4)第二问图就
A=(最大值-最小值)/2=2,b=(最大值+最小值)/2=1,周期T:T/2=2π/3-π/6=π/2,T=π,W=2,所以,f(x)=2sin(2x+φ)+1,代入最大值点(π/6,3),化简,s
周期是(x0+π/2-x0)*2=π所以T=2π/w=πw=2最大值为3所以A=3f(x)=3sin(2x+φ)f(0)=3sinφ=3/2|φ|
A=2T=4*[π/6-(-π/6)]=4π/3w=2π/(4π/3)=1.5f(x)=2sin(1.5x+φ)2sin(1.5*π/6+φ)=2π/6+φ=π/2φ=π/3f(x)=2sin(1.5
已知函数fx=Asin(wx+α)+1(w>0.A>00
解析:因为f(x)=Asin(wx+φ)(A>0,w>0,0w=2所以,f(x)=2sin(2x+φ)==>f(π/12)=2sin(π/6+φ)=2==>φ=π/3所以,f(x)=2sin(2x+π
我已经算出函数y=f(x)+f(x+2)的简式y=2根号2cosπ/4x求当x∈[-6,-2/3]函数y的最大值与最小值以及相应的x值解析:∵y=2√2cos(π/4x)∴函数y周期为T=8,所以,当
已知函数fx=Asin(wx+φ),其中w>0.1)当A=w=2,φ=π/6时,函数g(x)=f(x)-m在[0,π/2]上有两个零点,求m的范围.2)当A=1,φ=π/6时,若函数fx图像的相邻两条
从图像可知A=2周期T=8∴2π/w=8w=π/4f(x)=2sin(π/4x+φ)f(1)=2sin(π/4+φ)=2sin(π/4+φ)=1π/4+φ=π/2+2kπ,k∈Zφ=π/4+2kπ,k
最大A=2半周期T/2=11π/12-5π/12=π/2T=2π/w=πw=2x=0则f(0)=2sin(2*0+φ)=1sinφ=1/2φ=π/6f(x)=2sin(2x+π/6)递增则2kπ-π/
A=2,T=3π*2,得w=1/3,代入,因为f(0)=1得φ=π/6f(x)=2sin(x/3+π/6)其余就可以得出来了再问:这里我已经算出来了,就是后面的不知道怎么做。
(1)观察图像可知:A=2T/4=5π/12-π/6=π/4T=π故w=2所以f(x)=2sin(2x+φ)而f(π/6)=2得到2*π/6+φ=π/2+2kπφ=π/6+2kπ而|φ|
已知函数fx=Asin(wx+)+B的一系列对应值如下表X-π/6π/35π/64π/311π/67π/317π/6Y-1131-113(1)根据表格提供的数据求函数y=f(x)的解析式(2)若对任意
T=π,w=2A=2,B=1Φ=-π/6f(x)=2sin(2x-π/6)+1f(kx)=2sin(2kx-π/6)+1周期为2π/32k=3k=3/2f(kx)=2sin(3x-π/6)+1x∈[0
(1)根据图像知A=1,T/4=7π/12-π/3=π/4∴T=2π/w=π,∴w=2x=7π/12时,y=min=-1∴2*7π/12+φ=2kπ+3π/2,k∈Zφ=2kπ+π/3,k∈Z∵|φ|