先化简(x 1分之x-x方-1分之x 3)除以x方-2x 1分之2x-6
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![先化简(x 1分之x-x方-1分之x 3)除以x方-2x 1分之2x-6](/uploads/image/f/2039457-57-7.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%28x+1%E5%88%86%E4%B9%8Bx-x%E6%96%B9-1%E5%88%86%E4%B9%8Bx+3%29%E9%99%A4%E4%BB%A5x%E6%96%B9-2x+1%E5%88%86%E4%B9%8B2x-6)
(x+1)/x²-2x²/(x+1)=1设(x+1)/x²=t,则方程变为:t-2/t=1,即:t²-t-2=0,即(t-2)(t+1)=0∴t1=2t2=-1
f(1/x)=1-x^2+1/x^2=-f(x)直接代入即可再问:能写的再具体点吗我不太明白谢谢再答:哦我把题目看错了你的题目是对的吗再问:嗯题目是对的加我Q1047763981这样说方便再答:我没有
x分之1,-x平方分之2,x立方分之4,-x四次方分之8,x五次方分之16……,猜想并探索规律,第n个分式是[(-2)^(n-1)]/x^n
把X方—3X+1=0两边除以X得X-3+x分之一=0,x+x分之一=3,变成x方分之一+2+x方=3,变成x方分之一+x方=1,
x方-5x+1=0两边除以x得∴x-5+1/x=0x+1/x=5两边平方得x²+2+1/x²=25x²+1/x²=23
x1+x2=5;x1x2=1;(1)x1/x2+x2/x1=(x1²+x2²)/(x1x2)=((x1+x2)²-2x1x2)/(x1x2)=(25-2)/1=23;(2
化简结果:-X的3次方分之一乘以(5X方-4分之1乘以X+2分之1)
x分之4再问:有过程吗他那个是x-1分之1-x+1分之1的再答:[1/(x-1)-1/(x+1)]/[x/(2x方-2)]=[2/(x方-1)]*[2(x方-1)/x]=(2*2)/x=x/4
1x-2x(x-2)=---+--------÷--------x(3x-1)^23x-111=---+------÷xx3x-13x-11=--------+-------x(3x-1)x(3x-1
把每个式子因式分解x的方+5x+4=(x+1)(x+4)x方-5x+6=(x-2)(x-3)………………
[3x/(x-1)-x/(x+1)]×(x²-1)/x=x[3(x+1)-(x-1)]/(x²-1)×(x²-1)/x=2x+4当x=√2-2时,原式=2x+4=2√2
=(x-4)/(x+1)(x-1)除以(x-4)(x+1)/(x+1)平方+1/(x-1)=(x-4)/(x+1)(x-1)乘以(x+1)平方/(x-4)(x+1)+1/(x-1)=(x-4)/(x+
x方-1分之x方+x化简2x(1+x)
(x-1)/(x^2+3x+2)+6/(2+x-x^2)-(10-x)/(4-x^2)=(x-1)/(x+1)(x+2)-6/(x+1)(x-2)-(x-10)/(x+2)(x-2)=[(x-1)(x
x/(x²+2x+1),(x-1)/(x²+x),1/(x²-1)式1:x/(x+1)²,式2:(x-1)/[x(x+1)],式3:1/[(x+1)(x-1)]
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-2或5又二分之一再问:过程?再答:2X²-3X-1=0(2X+1)(X-1)=0X1=-1/2,X2=1或者X1=1,X2=-1/2带到后面的式子就可以了