使分式2x²-4x+2
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![使分式2x²-4x+2](/uploads/image/f/1957133-29-3.jpg?t=%E4%BD%BF%E5%88%86%E5%BC%8F2x%C2%B2-4x%2B2)
=x\(2-x)-(2+x)(2-x)\(2-x)^2=x\(2-x)-(2+x)\(2-x)=(x-2-x)\(2-x)=-2\(2-x)=2\(x-2)
原分式方程化为:2x+1x(x+1)=56(x+1),方程的两边同乘6x(x+1),得6(2x+1)=5x,解得x=-67.检验:把x=-67代入6x(x+1)≠0,即x=-67是原分式方程的解.则原
(1)分式的值为0;∴3x-4=0x=4/3(2)分式有意义;x+2不等于0∴x不等于-2(3)分式的值为正数3x-4>03x-40x+24/3或x再问:第一问是x=4分之3还是x=3分之4???再答
{[(x²-4)/(x²-4x+4)]-(x-2)/(x+2)}/[x/(x-2)]=[(x+2)(x-2)/(x-2)²-(x-2)/(x+2)][(x-2)/x]=[
去分母得:2+x(x+2)=x2-4,解得:x=-3,经检验x=-3是分式方程的解.
x²+2x/x²-6x+9÷x²-4/x²-3x=x(x+2)/(x-3)^2*x(x-3)/(x+2)(x-2)=x^2/[(x-3)(x-2)]
当分母x-6≠0,即x≠6时,分式2x−6有意义;故答案是:x≠6.
4/5x+x/(5x-25)=5/(x^2-5x)(4x-20)/5x(x-5)+x^2/5x(x-5)=25/5x(x-5)4x-20+x^2=254x+x^2=45x^2+4x+2^2=45(x+
∵当△=b2-4ac<0时,x2+4x+m=0无解,即42-4m<0,解得m>4,∴当m>4时,不论x取何实数,分式总有意义.故答案为m>4.
(x-3)(x-2)-(x-4)(x-1))/((x-1)(x-2))=((x-5)(x-4)-(x-6)(x-3))/((x-3)(x-4))2/((x-1)(x-2))=2/((x-3)(x-4)
=(x+2)/x(x-2)-(x-1)/(x-2)²=(x+2)(x-2)/x(x-2)²-x(x-1)/x(x-2)²=(x²-4-x²+x)/x(
(x-2)/(x+2)=(x+2)/(x-2)+16/(x²-4)方程两边同时乘(x²-4)(x-2)²=(x+2)²+16x²-4x+4=x
﹛x-3≠0x+2≠0x-4≠0∴x的取值范围是x≠-2,且x≠3且x≠4的实数
档分母=0时,无意义x^2-5x-6=0x=-1或6当分子=0,分母不等于0时,分时=0,首先要保证分式有意义x^2-3x-4x=-1或4取x=4(-1时,分式无意义)
当分子2x+4=0,即x=-2时,分式2x+4x+1的值为0;当分母3x-9≠0,即x≠3时,分式x3x−9有意义.
∵分式2x+12x−1无意义,∴2x-1=0,∴x=12.故答案为:12.
两边同乘x²-4(x-2)²=(x+2)²+16x²-4x+4=x²+4x+4+16-8x=16x=-2
4x/2x-1=2x-1/x-2(2x-1)*(2x-1)=4x*(x-2)x=-1/4