从键盘输入一个4位数的正整数n,将该数反序输出.

intaddsum(intm,intn){intm,ncin>>m>>n;if(m<n)cout<<"错误,m<n"<<endl;intsu

可参考如下scanf("%d",&num);printf("%d\n",num/100);printf("%d\n",num%10);---------------------------------

#include <stdio.h>int main(void){     int n; &nbs

#includevoidmain(){\x09intn,i,j,t,a[10000];\x09printf("请输入正整数N:");\x09scanf("%d",&n);\x09printf("请依次

利用数组a[5]for(i=0;i0;i--）；printf（"%d",a[i]）;

#includevoidmain(){chars[12];inti,L;gets(s);L=strlen(s);//几位数printf("L=%d\n",L);for(i=0;i=0;i--)//从低

#includeintfact(intn);usingnamespacestd;intmain(){intn;cin>>n;cout

#include#includedoublefun(intn);intmain(){printf("Inputn:");intn;scanf("%d",&n);doubleS=fun(n);

#includeintmain(){intn,num,max,min;scanf("%d",&n);for(inti=n;i>0;i--){scanf("%d",&num);if(i==n)//初始化

#includeintmain(){inta;intsum=0;scanf("%d",&a);if(a

#includemain(){intn,i,j,k=0,sum=0,a[100];printf("请输入一个数字\n");scanf("%d",&n);for(i=1;i

#include#includeintfactorial(intn);doublefact(intn);doublepower(intn);intmain(){inti,j;\x05doubleff=

你好像对C语言的赋值符号不理解?e=(1000*a)+(100*b)+(10*c)+(1*d);这样是把(1000*a)+(100*b)+(10*c)+(1*d)的值赋给e,而不是把e分解成a,b,c

#includeusingnamespacestd;voidmain(){intn,i,j=0,k=0,a[100],b[100];//a[100]用来存放奇数,b[100]用来存放偶数cout

staticvoidMain(string[]args){inta=int.Parse(Console.ReadLine());intb=a%10;intc=(a/10)%10;intd=(a/100

从键盘输入一个自然数N(

OptionBase1PrivateSubCommand1_Click()n=InputBox("请输入一个正整数")Fori=1ToLen(n)Sum=Sum+Val(Mid(n,i,1))Next

#include#include#includemain(){inti,n;longj,k,sum=0;printf("inputthen:\n");scanf("%d",&n);/*n为项数*/fo

PrivateSubForm_Click()Dimi,n,tAsIntegerDimsAsSingles=0t=1n=InputBox("n=")Fori=1Ton-1s=s+t*i/(i+1)t=-

#include <stdio.h>int main() {int stat[11];int num, i;for&nbs