(x-y分之1+x+y分之1)÷x²-y²分之2x-y
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![(x-y分之1+x+y分之1)÷x²-y²分之2x-y](/uploads/image/f/15741-45-1.jpg?t=%28x-y%E5%88%86%E4%B9%8B1%2Bx%2By%E5%88%86%E4%B9%8B1%29%C3%B7x%C2%B2-y%C2%B2%E5%88%86%E4%B9%8B2x-y)
原式=[(x+2y)/(x+y)][xy/(x+2y)]÷[(x+y)/xy]=[xy/(x+y)]×xy/(x+y)=x²y²/(x+y)²
这是反比例函数.图像是位于一、三象限的双曲线.由于x<0,因此函数图象为双曲线的第三象限部分手工绘图应用描点法.见下图
答除了5x+2=y其他的2分之1x=y2x=3分之2y0.5分之y=3分之x7分之x=3分之y0.7y=x他们成正比例原因他们都满足y=kx(k≠0)的形式,两个量满足y=kx(k≠0)的形式,则两个
=(2X/3Y)*(3X/4Y)*(4/xy)=(2x*3x*4)/(3y*4y*xy)=2x/(y^3)
1x^2y分之x^4=x²/y2ab分之ab-b^2(b不等于0)=1-b/a36abc^2分之36ab^3c=6b²/c4a^2-b^2分之(a+b)^3=(a+b)²
3)把①式乘以10,②式乘以6,得:25x+2y=-402x+y=1由下式得y=1-2x,代入上式得25x+2-4x=-4021x=-42x=-2则y=1+4=54)把①式乘以6,②式乘以2得3x-y
(根号y分之x-根号x分之y)除以(根号y分之1-根号x分之1)=[(x-y)/根号xy]÷[(根号x-根号y)/根号xy]=根号x+根号y
3分之x+1=2分之y+2=2分之x+y解;每项乘62x+2=3y+2=3x+3y再问:要算出x和y。。这一步已经算出来了,后面不知道该怎么算了。。。再答:不好意思,前面是每项乘62x+4=3y+2=
第一个两边乘128(x-y)-3(x+y)=-128x-8y-3x-3y=-125x-11y=-12(1)第二个6x+6y-8x+4y=16-2x+10y=16x-5y=-8(2)(1)-(2)×55
原式=1/2x-1/(x+y)[(x+y)/2x-(x+y)]=1/2x-(1/2x-1)=1/2x-1/2x+1=1
1、(xy分之x²-y²)×(x-y分之x)-(y分之x);=(x+y)(x-y)/xy×x/(x-y)-x/y=(x+y)/y-x/y=(x+y-x)/y=12、6xy²
原式=[(x+2y)/(x+y)]×[xy/(x+2y)]÷[(x+y)/xy]=[(x+2y)/(x+y)]×[xy/(x+2y)]×[xy/(x+y)]=x²y²(x+2y)/
解1题原式=[(x+y)/x]-[x/(x-y)]+[y²/(x²-xy)]=[(x+y)/x]-[x/(x-y)]+{y²/[x(x-y)]}={(x+y)(x-y)/
(1-y+x分之y)÷y的平方-x的平方分之x=[(y+x-y)/(y+x)]÷x/(y²-x²)=x/(y+x)*[(y+x)(y-x)/x]=y-x
是这样的形式吗?[x/(x+y)+2y/(x+y)]×[xy/(x+y)]÷(1/x+1/y)一:原式=(x+2y)/(x+y)×[xy/(x+2y)]÷[(x+y)/xy]=x²y&sup
分子上应写:(x-1)²或者x²-2x+1再问:怎么书面表达呢?能否详细一些,谢谢再答:希望你及时采纳!!!!!
设1/(x-y)=a,1/(x+y)=b则原方程组变成:2a+b=1/4b-a=1解得:a=-1/4,b=3/4则1/(x-y)=-1/41/(x+y)=3/4解得:x=-4/3,y=8/3
1/x+1/y=-1/(x+y)两边同时乘x+y得1+y/x+1+x/y=-1所以y/x+x/y=-3