2. 输入1 个正整数 n, 计算并输出 s 的前n项的和.
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![2. 输入1 个正整数 n, 计算并输出 s 的前n项的和.](/uploads/image/f/129982-22-2.jpg?t=2.+%E8%BE%93%E5%85%A51+%E4%B8%AA%E6%AD%A3%E6%95%B4%E6%95%B0+n%2C+%E8%AE%A1%E7%AE%97%E5%B9%B6%E8%BE%93%E5%87%BA+s+%E7%9A%84%E5%89%8Dn%E9%A1%B9%E7%9A%84%E5%92%8C.)
s=0;for(i=1;i
#includeintmain(){intn,num,max,min;scanf("%d",&n);for(inti=n;i>0;i--){scanf("%d",&num);if(i==n)//初始化
intjie_cheng(intn){if(n==1)return1;returnn*jie_cheng(n-1);}doublefact(intn){doublesum=0;for(inti=1;i
#includeusingnamespacestd;intmain(){inti;doublee,n,sum;cin>>n;for(i=0,e=-1,sum=0;i{e*=-1;sum+=e*1/(2
#includeintmain(void){intn;inti;doublesum=0.0;intfact=1;scanf("%d",&n);for(i=1;i
intprime(inti){intj;\x05if(i==1)return0;for(j=2;j
#includeintmain(){intn,i,j;intflag;printf("请输入>2的整数:");scanf("%d",&n);printf("这个数的所有素数:");for(i=3;i
C程序设计:输入2个正整数m和n(1<=m,n<=500),统计并输出m和n之间的素数个数以及这些素数的和.输入:m和n;输出:素数个数以及这些素数的和.
#includeintmain(){intm,n;inti,j,s,d;printf("请输入m:");scanf("%d",&m);printf("请输入n:");scanf("%d",&n);pr
#include<stdio.h>#include<math.h>main(){ intc,a[10]={0}; inti,j,k=0,n,x;
没有仔细看,但是有一处有问题,你试试看.if(i=is(i))为什么碰到一个i满足要求时,要将i重新赋值为1呢?!改为:if(is(i))
是要编程序么再问:C语言编程再答:#includeintjiecheng(intn){inti,mul=1;for(i=1;i
#includeintmain(){intn,i,x,a=0,b=0;scanf("%d",&n);for(i=1;i
PrivateSubCommand1_Click()Sum=1Fori=1ToText1.TextSum=Sum*iNextiPrintSumEndSub再问:那在窗体上输出九九乘法表??你会吗??真
#includeintfact(intn){intt=1;for(inti=1;i
importjava.io.*;publicclassTest{publicstaticvoidmain(String[]args){BufferedReaderbr=newBufferedReade
#includevoidmain(){intn,i,a,b,c,d,e;floats,sum=0,ave;a=b=c=d=e=0;printf("请输入学生个数:");scanf("%d",&n);p
#include#include#includeintmain(void){intn=0,sum=0;int*nums;printf("请输入整数个数:\n");scanf("%d",&n);nums